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Q. |
If a= net area of diagram in mm², l= length of indicator diagram in cm & k= spring constant in N/m²/m the imp in bar equals |
A. | (a/l)xk |
B. | (a/l) x k x 10ˉ⁹ |
C. | (a/l) x k x 10ˉ⁶ |
D. | (a/l) x k x 10ˉ³ |
Answer» B. (a/l) x k x 10ˉ⁹ |
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