Q.

If a= net area of diagram in mm², l= length of indicator diagram in cm & k= spring constant in N/m²/m the imp in bar equals

A. (a/l)xk
B. (a/l) x k x 10ˉ⁹
C. (a/l) x k x 10ˉ⁶
D. (a/l) x k x 10ˉ³
Answer» B. (a/l) x k x 10ˉ⁹
2.1k
0
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