A declaration "short int" is used for variables

Related MCQs

• What will be output if you will compile and execute the following c code? #include<stdio.h> int * call(); int main(){ int *ptr; ptr=call(); printf("%d",*ptr); return 0; } int * call(){ int a=25; a++; return &a; }
• What will be the output of the program? #include<stdio.h> int i; int fun(); int main() { while(i) { fun(); main(); } printf("Hello\n"); return 0; } int fun() { printf("Hi"); }
• What will be the output of the following code? Void main(){int a=10;int *b=&a;int **c=&b;printf("%d %d %d",a,*b,**c);}
• What will be output if you will compile and execute the following c code? #include<stdio.h> int main(){ int i=10; static int x=i; if(x==i) printf("Equal"); else if(x>i) printf("Greater than"); else printf("Less than"); return 0; }
• What will be the output of the program? #include<stdio.h> int main() { int X=40; { int X=20; printf("%d ", X); } printf("%d\n", X); return 0; }
• What will be output if you will compile and execute the following c code? #include<stdio.h> int main(){ int i=320; char *ptr=(char *)&i; printf("%d",*ptr); return 0; }
• What will be output if you will compile and execute the following c code? #include<stdio.h> #define x 5+2 int main(){ int i; i=x*x*x; printf("%d",i); return 0; }
• What will be output if you will compile and execute the following c code? #include<stdio.h> int main(){ int i=4,x; x=++i + ++i + ++i; printf("%d",x); return 0; }
• What will be output if you will compile and execute the following c code? #include<stdio.h> int main(){ int a=2; if(a==2){ a=~a+2<<1; printf("%d",a); } else{ break; } return 0; }
• What will be output if you will compile and execute the following c code? #include<stdio.h> int main(){ int a=10; printf("%d %d %d",a,a++,++a); return 0; }