A. Six turns of Calvin-cycle result in the production of one molecule of glucose (C6H12O6) R. Three molecules of ribulose 1, 5 – bisphosphate (Ru BP) react with three molecules of carbon dioxide to produce six carbon intermediates.

Related MCQs

• The Calvin cycle proceeds in three stages 1. reduction, during which carbohydrate is formed at the expense of the photochemically made ATP and NADPH 2. regeneration, during which the carbon dioxide acceptor ribulose – 1, 5 – biphosphate is formed 3. carboxylation, during which carbon dioxide combines with ribulose – 1, 5 - biophosphate
• Match the terms in column-I with suitable terms in column-II Column – I Column – II P C6H10O5 i Glyceraldehyde Q C3H6O3 ii Galactose R C5H10O4 iii Ribulose S C6H12O6 iv Deoxy ribose sugar
• To produce 3 glucose molecules ______ ATP and ______ NADPH2 molecules are required.
• The number of ATP molecules formed in oxidative phosphorylation of one glucose molecule
• How many ATP molecules are released when one molecule of glucose is oxidised in our liver cells (CP.M.t:2’ob5)
• During dark reaction, for the fixation of carbon, the three carbon atoms of each molecule of 3 – phosphogylceric acid (PGA) are derived from
• How many molecules of NADH2 are produced when four molecules of phosphogyceraldehyde arc converted into four molecules of pyruvate (Guj.CET. 2006)
• For synthesis of one glucose molecule, the number of ATP required are
• For synthesis of one molecule of glucose, the requirement of ATP and NADPH2 is respectively
• ATP equivalents produced during oxidation of succinate to fumarate for one glucose molecule is/are (R.PMT.1988)