Which of the following does NOT increase renal tubular sodium reabsorption?

Related MCQs

• Substance X is freely filtered by the glomerulus and is not reabsorbed, nor secreted nor metabolized. If - serum x concentration = 0.020 mg/ml renal artery x concentration = 0.020 mg/ml renal vein x concentration = 0.002 mg/ml urine x concentration = 14 mg/ml urine flow = 54 ml/hr lymphatic x concentration = 0.00001 mg/ml haematocrit = 0.45 Renal plasma flow is:
• Substance X is freely filtered by the glomerulus and is not reabsorbed, nor secreted nor metabolized. If - serum x concentration = 0.020 mg/ml renal artery x concentration = 0.020 mg/ml renal vein x concentration = 0.002 mg/ml urine x concentration = 14 mg/ml urine flow = 54 ml/hr lymphatic x concentration = 0.00001 mg/ml haematocrit = 0.45 Renal blood flow is:
• Regarding tubular reabsorption in kidney:
• Which of the following substances is NOT actively secreted in to the tubular lumen by the proximal renal tubule?
• Which of the following statements regarding renal tubular glucose absorption is INCORRECT?
• All of the following are transported across renal tubular cell membranes by secondary active transport, using the energy of the active transport of Na+ , EXCEPT:
• Regarding the osmolality of renal tubular fluid, is it?
• Regarding renal tubular function:
• Substance X is freely filtered by the glomerulus and is not reabsorbed, nor secreted nor metabolized. If - serum x concentration = 0.020 mg/ml renal artery x concentration = 0.020 mg/ml renal vein x concentration = 0.002 mg/ml urine x concentration = 14 mg/ml urine flow = 54 ml/hr lymphatic x concentration = 0.00001 mg/ml haematocrit = 0.45 Then the CLEARANCE of X is:
• Substance X is freely filtered by the glomerulus and is not reabsorbed, nor secreted nor metabolized. If - serum x concentration = 0.020 mg/ml renal artery x concentration = 0.020 mg/ml renal vein x concentration = 0.002 mg/ml urine x concentration = 14 mg/ml urine flow = 54 ml/hr lymphatic x concentration = 0.00001 mg/ml haematocrit = 0.45 The GFR is: