Q.

What is the distance between the lines 3x- 4y+7=0 and 3x-4y+5=0?

A. 1 unit
B. 0.5 unit
C. 0.8 unit
D. 0.4 unit
Answer» D. 0.4 unit
Explanation: as the given lines are parallel so the distance between them can be calculated by using the formula (c1- c2)/(√a2+b2). so we get the distance as 0.4 unit.
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