

McqMate
These multiple-choice questions (MCQs) are designed to enhance your knowledge and understanding in the following areas: Common Topics in Competitive and Entrance exams .
151. |
Cache memory is |
A. | Bigger and slower than main memory |
B. | Bigger and faster that main memory |
C. | Smaller and slower than main memory |
D. | Smaller and faster than main memory |
Answer» D. Smaller and faster than main memory |
152. |
By principle of locality, cache memory |
A. | Increases average memory access time. |
B. | Reduces average memory access time |
C. | Does not affect the average memory access time |
D. | None of these |
Answer» B. Reduces average memory access time |
153. |
Following is not true for disk cache |
A. | It is a buffer in main memory for disk sector |
B. | It contains the copy of some of the sector on the disk |
C. | It is bigger is size than main memory |
D. | It is smaller is size than main memory |
Answer» C. It is bigger is size than main memory |
154. |
In disk storage devices, data are recorded on and later retrieved from disk via a conducting coil named |
A. | Tail |
B. | Foot |
C. | Head |
D. | Hand. |
Answer» C. Head |
155. |
In disk storage devices during read and write operation |
A. | Head is rotate while platter is stationary |
B. | Head is stationary while platter rotates |
C. | Head and platter are both stationary |
D. | None is true |
Answer» B. Head is stationary while platter rotates |
156. |
In magnetic disk, density that is in bits per linear inch |
A. | Increases in moving from the outer most track to the inner most track. |
B. | Decreases in moving from the outer most track to the inner most track. |
C. | Remains same in moving from the outer most track to the inner most track. |
D. | Randomly distributed in moving from the outer most track to the inner most track. |
Answer» A. Increases in moving from the outer most track to the inner most track. |
157. |
Data from and to magnetic disk is transformed in |
A. | Continuation |
B. | Blocks |
C. | Block and Continuation both |
D. | None of these. |
Answer» B. Blocks |
158. |
On magnetic disks, the data on the platter is organized in a concentric sets of rings called |
A. | Sectors |
B. | Gaps |
C. | Rings |
D. | Tracks |
Answer» D. Tracks |
159. |
In disk storage devices the width of head is: |
A. | Same of the track |
B. | More than of the track |
C. | Less than of the track |
D. | None is true. |
Answer» A. Same of the track |
160. |
In a fixed head disk, the number of read/write head per track are |
A. | One |
B. | Two |
C. | Three |
D. | Four. |
Answer» A. One |
161. |
CD defines |
A. | Computer device |
B. | Computer disk |
C. | Compact disk |
D. | None of these |
Answer» C. Compact disk |
162. |
A-Fixed-Head disk, B-Movable-Head disk, 1- One head per track and al head are mounted on rigid arm that extends across all tracks. 2- Only one head and head is mounted on the arm, such that it can position the track. |
A. | A – 1, B – 2 |
B. | A – 2, B – 1 |
C. | A – 1, B – 1 |
D. | A – 2, B – 2 |
Answer» A. A – 1, B – 2 |
163. |
The record is the collection of |
A. | Fields |
B. | Files |
C. | Data base |
D. | None of these. |
Answer» A. Fields |
164. |
In File system architecture which is the correct arrangement from lower level to higher. |
A. | Device drives, basic file system, basic I/ O supervisor, logical I/O. |
B. | Basic file system, basic I/O, logical I/O, device drives. |
C. | Basic I/O, basic file system, logical I/O, device drives. |
D. | None of these. |
Answer» A. Device drives, basic file system, basic I/ O supervisor, logical I/O. |
165. |
In file management system the following communicate directly with periphing I/O devices. |
A. | Device drives |
B. | Basic file system |
C. | Basic I/O supervisor |
D. | Logical I/O. |
Answer» A. Device drives |
166. |
For file management, in file operations device drivers are |
A. | Disk drivers |
B. | Tape drivers |
C. | A and B both |
D. | None of these. |
Answer» C. A and B both |
167. |
In file management, the primary interface of computer system with external environment is done through |
A. | Device drivers |
B. | Basic file system |
C. | Basic I/O supervisor |
D. | Logical I/O. |
Answer» B. Basic file system |
168. |
In file management, users and applications access records via |
A. | Physical I/O |
B. | Basic I/O supervisor |
C. | Logical I/O |
D. | None of these. |
Answer» C. Logical I/O |
169. |
Match the following for file system architecture : A-Basic file system, B-Logical I/O module, 1- Deals with blocks of data, 2- Deals with file records, 3- Provides general purpose record I/O capacity. |
A. | A – 1, B – 2, 3 |
B. | A – 1, 2, B – 3 |
C. | A – 2, 3, B – 1 |
D. | A – 1, 3, B – 2 |
Answer» A. A – 1, B – 2, 3 |
170. |
Match the following access rights :A-Specific user, B-User group, C-All ; 1- Individual user who are designated by user I, 2-A set of users who are individually defined, 3-Every user has access to the system. |
A. | A – 1, B – 2, C – 3 |
B. | A – 2, B – 1, C – 3 |
C. | A – 1, B – 3, C – 2 |
D. | A – 3, B – 2, C – 1 |
Answer» A. A – 1, B – 2, C – 3 |
171. |
In file management, the pile |
A. | The collection of data in order which they arrive. |
B. | A fixed format used for records. |
C. | Records keep with some key sequence. |
D. | None of these. |
Answer» A. The collection of data in order which they arrive. |
172. |
In file management, in the following record blocking method, the optional use of space is made, without unused space left |
A. | Fixed blocking |
B. | Variable-length spanned blocking |
C. | Variable-length un-spanned blocking |
D. | None of these. |
Answer» B. Variable-length spanned blocking |
173. |
In secondary storage management, “If allocation of file is made on an individual block basis and each block contains a pointer to the next block in the chain” then it is referred as |
A. | Contiguous allocation |
B. | Chained allocation |
C. | Indexed allocation |
D. | None of these. |
Answer» B. Chained allocation |
174. |
In secondary storage management, bit table, for each block on disk a vector contains |
A. | One bit each block |
B. | Two bit each block |
C. | Three bit each block |
D. | Four bit each block. |
Answer» A. One bit each block |
175. |
In bit table used for Free space management in secondary storage |
A. | Bit zero corresponds to free block |
B. | Bit one corresponds to free block |
C. | Bit zero corresponds to block in use |
D. | None of these |
Answer» A. Bit zero corresponds to free block |
176. |
The amount of memory (in bytes) required for a block bitmap is |
A. | Disk size × 8 |
B. | Disk size/ (8 × file system block size) |
C. | File system block size/disk size |
D. | None of these. |
Answer» B. Disk size/ (8 × file system block size) |
177. |
In 16 G byte disk with 512-bit block, the bit table requires |
A. | 1 M bytes |
B. | 2 M bytes |
C. | 3 M bytes |
D. | 4 M bytes. |
Answer» D. 4 M bytes. |
178. |
Application Programming Interface is |
A. | A set of function and call programs that allows clients and servers to intercommunicate. |
B. | A database, where information access is limited to the selection of rows that satisfy all search criteria. |
C. | A computer usually a high powered work station. |
D. | None of these. |
Answer» A. A set of function and call programs that allows clients and servers to intercommunicate. |
179. |
If in a computer networking environment when all the processing is done on single computer can be referred as |
A. | Host based processing |
B. | Server based processing |
C. | Client based processing |
D. | None of these. |
Answer» A. Host based processing |
180. |
In three tier client/server architecture application software match the following: A- User machine, 1-Client, B- Middle-tier, 2- Application server, C- Backend server, 3 Data servers. |
A. | A – 1, B – 2, C – 3 |
B. | A – 1, B – 3, C – 2 |
C. | A – 2, B – 1, C – 3 |
D. | A – 3, B – 2, C – 1 |
Answer» A. A – 1, B – 2, C – 3 |
181. |
UNIX was developed by |
A. | Bell Labs for PDP-7 in 1970 |
B. | Microsoft for IBM computers |
C. | Macintosh |
D. | None of these. |
Answer» A. Bell Labs for PDP-7 in 1970 |
182. |
UNIX is a |
A. | Operating system |
B. | Hardware |
C. | Programming language |
D. | None of these. |
Answer» A. Operating system |
183. |
In UNIX process management, the system process runs in |
A. | Kernel mode only |
B. | Kernel and user mode both |
C. | User mode only |
D. | None of these. |
Answer» A. Kernel mode only |
184. |
In UNIX process management, the user processes runs in |
A. | Kernel mode only |
B. | Kernel and user mode both |
C. | User mode only |
D. | None of these. |
Answer» B. Kernel and user mode both |
185. |
In UNIX process management, the following is true |
A. | User process enters kernel mode by issuing a system call when interrupt occurs. |
B. | Kernel mode is executed in user process. |
C. | User process enters kernel mode with out issuing a system call when interrupt occurs. |
D. | None of these. |
Answer» A. User process enters kernel mode by issuing a system call when interrupt occurs. |
186. |
The number of process states recognized by UNIX |
A. | Two |
B. | Nine |
C. | Eight |
D. | Seven. |
Answer» B. Nine |
187. |
In process management of UNIX system, which of the following process states are running states in respect of whether the process is executing in user or kernel mode |
A. | Ready to run (in memory) state |
B. | Ready to run (in swappe(D) state |
C. | Preempted state |
D. | A and C are true |
Answer» D. A and C are true |
188. |
A task in a blocked state is |
A. | Executable |
B. | Waiting for some temporarily unavailable resource |
C. | Running |
D. | None of these |
Answer» B. Waiting for some temporarily unavailable resource |
189. |
Semaphores |
A. | are used to do I/O |
B. | Synchronize critical resources to prevent contention |
C. | synchronize critical resources to prevent deadlock. |
D. | allow processes to communicate with one another. |
Answer» C. synchronize critical resources to prevent deadlock. |
190. |
Priorities |
A. | are used to schedule processes |
B. | increase as a process remains in the processor |
C. | are attached to each page in the system |
D. | are assigned by the user. |
Answer» A. are used to schedule processes |
191. |
Dijkstra’s banker’s algorithm in an operating-system solves the problem of |
A. | deadlock avoidance |
B. | deadlock recovery |
C. | mutual exclusion |
D. | context switching |
Answer» A. deadlock avoidance |
192. |
Which structure prohibits the sharing of files and directories |
A. | tree structure |
B. | one level structure |
C. | two level structure |
D. | none of these |
Answer» D. none of these |
193. |
With round-robin CPU scheduling in a time shared system |
A. | using very large time slices degenerates into First-Come First Served Algorithm |
B. | using extremely small time slices improves performance |
C. | using very small time slices degenerate into Last-In-First-Out algorithm |
D. | using medium sized time slices leades to Shortest Request Time First algorithm. |
Answer» A. using very large time slices degenerates into First-Come First Served Algorithm |
194. |
The portion of the process scheduler in an operating system that dispatches processes is concerned with |
A. | activating suspended I/O-bound processes |
B. | temporarily suspending processes when CPU load is too great |
C. | assigning ready processes to the CPU |
D. | all of the above |
Answer» C. assigning ready processes to the CPU |
195. |
Following is the correct definition of a valid process transition within an operating system |
A. | wake up : ready – running |
B. | dispatch: ready – running |
C. | block: ready – blocked |
D. | timer run out : ready – blocked |
Answer» B. dispatch: ready – running |
196. |
I/O redirection |
A. | implies changing the name of a file |
B. | can be employed to use an exiting file as input file for a program |
C. | implies connection to programs through a pipe |
D. | none of the above |
Answer» B. can be employed to use an exiting file as input file for a program |
197. |
When an interrupt occurs, an operating system |
A. | ignores the interrupt |
B. | always changes state of interrupted process after processing the interrupt |
C. | always resumes execution of interrupted process after processing the interrupt |
D. | may change state of interrupted process to blocked and schedule another process |
Answer» D. may change state of interrupted process to blocked and schedule another process |
198. |
Thrashing |
A. | reduces page I/O |
B. | decreases the degree of multi- programming |
C. | implies excessive page I/O |
D. | improve the system performance |
Answer» C. implies excessive page I/O |
199. |
Dirty bit for a page in a page table |
A. | helps avoid unnecessary writes on a paging device |
B. | helps maintain LRU information |
C. | allows only read on a page |
D. | none of the above |
Answer» A. helps avoid unnecessary writes on a paging device |
200. |
A disk scheduling algorithm in an operating system causes the disk arm to seek back and forth access the disc surface servicing all request in its path, this is a |
A. | first come first served |
B. | shortest seek time first |
C. | scan |
D. | None of these |
Answer» C. scan |
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