McqMate
These multiple-choice questions (MCQs) are designed to enhance your knowledge and understanding in the following areas: Civil Engineering .
| 101. |
The moment of inertia of a body is always minimum with respect to its |
| A. | Base |
| B. | Centroidal axis |
| C. | Vertical axis |
| D. | Horizontal axis |
| Answer» B. Centroidal axis | |
| 102. |
Moment of inertia is the |
| A. | Second moment of area |
| B. | Second moment of mass |
| C. | Second moment of force |
| D. | All of these |
| Answer» D. All of these | |
| 103. |
In a simply supported beam carrying a uniformly distributed load W/m over the left half span, the point of contra flexure will occur in |
| A. | Left half span of the beam |
| B. | Right half span of the beam. |
| C. | Quarter points of the beam |
| D. | Does not exist |
| Answer» D. Does not exist | |
| 104. |
A sudden increase or decrease in shear force diagram between any two points indicates that there is |
| A. | No loading between the two points |
| B. | Point loads between the two points |
| C. | U.D.L. between the two points |
| D. | None of these |
| Answer» B. Point loads between the two points | |
| 105. |
When the bending moment is parabolic curve between two points, it indicates that there is |
| A. | No loading between the two points |
| B. | Point loads between the two points |
| C. | U.D.L. between the two points |
| D. | Uniformly varying load between the two points |
| Answer» C. U.D.L. between the two points | |
| 106. |
In Fig.(a), max B.M. will be |
| A. | 40 kN-m |
| B. | 50 kN-m |
| C. | 60 kN-m |
| D. | 80 kN-m |
| Answer» B. 50 kN-m | |
| 107. |
In Fig. (a), slope of S.F.D. between B and C will be |
| A. | Zero |
| B. | 10 kN |
| C. | 15 kN |
| D. | 20 kN |
| Answer» A. Zero | |
| 108. |
What is the bending moment at end supports of a simply supported beam? |
| A. | Maximum |
| B. | Minimum |
| C. | Zero |
| D. | Uniform |
| Answer» C. Zero | |
| 109. |
What is the maximum shear force, when a cantilever beam is loaded with udl throughout? |
| A. | w×l |
| B. | w |
| C. | w/l |
| D. | w+l |
| Answer» A. w×l | |
| 110. |
Sagging, the bending moment occurs at the of the beam. |
| A. | At supports |
| B. | Mid span |
| C. | Point of contraflexure |
| D. | Point of emergence |
| Answer» B. Mid span | |
| 111. |
What will be the variation in BMD for the diagram? [Assume l = 2m]. |
| A. | Rectangular |
| B. | Trapezoidal |
| C. | Triangular |
| D. | Square |
| Answer» C. Triangular | |
| 112. |
What is the maximum bending moment for simply supported beam carrying a point load “W” kN at its centre? |
| A. | W kNm |
| B. | W/m kNm |
| C. | W×l kNm |
| D. | W×l/4 kNm |
| Answer» D. W×l/4 kNm | |
| 113. |
How do point loads and udl be represented in SFD? |
| A. | Simple lines and curved lines |
| B. | Curved lines and inclined lines |
| C. | Simple lines and inclined lines |
| D. | Can’t represent any more |
| Answer» C. Simple lines and inclined lines | |
| 114. |
curve is formed due to bending of overhanging beams. |
| A. | Elastic |
| B. | Plastic |
| C. | Flexural |
| D. | Axial |
| Answer» A. Elastic | |
| 115. |
The relation between slope and maximum bending moment is |
| A. | Directly proportion |
| B. | Inversely proportion |
| C. | Relative proportion |
| D. | Mutual incidence |
| Answer» B. Inversely proportion | |
| 116. |
What is the SF at support B? |
| A. | 5 kN |
| B. | 3 kN |
| C. | 2 kN |
| D. | 0 kN |
| Answer» D. 0 kN | |
| 117. |
Where do the maximum BM occurs for the below diagram. |
| A. | -54 kNm |
| B. | -92 kNm |
| C. | -105 kNm |
| D. | – 65 kNm |
| Answer» C. -105 kNm | |
| 118. |
Shear force is unbalanced to the left or right of the section. |
| A. | Horizontal force |
| B. | Vertical force |
| C. | Inclined force |
| D. | Conditional force |
| Answer» B. Vertical force | |
| 119. |
SI units of shear force is |
| A. | kN/m |
| B. | kN-m |
| C. | kN |
| D. | m/N |
| Answer» C. kN | |
| 120. |
Determine the moment at fixed end. |
| A. | 40 kNm |
| B. | 50 kNm |
| C. | 60 kNm |
| D. | 80 kNm |
| Answer» D. 80 kNm | |
| 121. |
Shear force diagram is representation of shear force plotted as ordinate. |
| A. | Scalar |
| B. | Aerial |
| C. | Graphical |
| D. | Statically |
| Answer» C. Graphical | |
| 122. |
Hogging is |
| A. | Negative bending moment |
| B. | Positive shear force |
| C. | Positive bending moment |
| D. | Negative shear force |
| Answer» A. Negative bending moment | |
| 123. |
At the point of contraflexure, the value of bending moment is |
| A. | Zero |
| B. | Maximum |
| C. | Can’t be determined |
| D. | Minimum |
| Answer» A. Zero | |
| 124. |
Positive/negative bending moments occur where shear force changes its sign. |
| A. | Minimum |
| B. | Zero |
| C. | Maximum |
| D. | Remains same |
| Answer» C. Maximum | |
| 125. |
Shear force of following diagram |
| A. | Rectangle |
| B. | Square |
| C. | Circle |
| D. | Trapezoidal |
| Answer» A. Rectangle | |
| 126. |
SI units of Bending moment is |
| A. | kN |
| B. | kN2 |
| C. | kNm |
| D. | km |
| Answer» C. kNm | |
| 127. |
What is the other name for a positive bending moment? |
| A. | Hogging |
| B. | Sagging |
| C. | Inflation |
| D. | Contra flexure |
| Answer» B. Sagging | |
| 128. |
For any part of the beam, between two concentrated load Shear force diagram is a |
| A. | Horizontal straight line |
| B. | Vertical straight line |
| C. | Line inclined to x-axis |
| D. | Parabola |
| Answer» A. Horizontal straight line | |
| 129. |
For any part of a beam subjected to uniformly distributed load, bending moment diagram is |
| A. | Horizontal straight line |
| B. | Vertical straight line |
| C. | Line inclined to x-axis |
| D. | Parabola |
| Answer» D. Parabola | |
| 130. |
A sudden jump anywhere on the Bending moment diagram of a beam is caused by |
| A. | Couple acting at that point |
| B. | Couple acting at some other point |
| C. | Concentrated load at the point |
| D. | Uniformly distributed load or Uniformly varying load on the beam |
| Answer» A. Couple acting at that point | |
| 131. |
The diagram shown below, depicts bending diagram for |
| A. | cantilever beam with uniformly distributed load |
| B. | cantilever beam with uniformly distributed load only on half side of the beam |
| C. | simply supported beam with varying distributed load |
| D. | simply supported beam with uniformly distributed load |
| Answer» D. simply supported beam with uniformly distributed load | |
| 132. |
A 10 m long cantilever beam is fixed at point B. What is the bending moment at point B, if 5 m span of AC carries uniform distributed load of 10 kN/m |
| A. | 125 kN/m |
| B. | 200 kN/m |
| C. | 375 kN/m |
| D. | 500 kN/m |
| Answer» C. 375 kN/m | |
| 133. |
What is the maximum shear force acting on the beam shown below. |
| A. | 125 N |
| B. | 200 N |
| C. | 4000 N |
| D. | 8000 N |
| Answer» B. 200 N | |
| 134. |
At a point in a simply supported or overhanging beam where Shear force changes sign and Bending moment is |
| A. | Maximum |
| B. | Zero |
| C. | Either increasing or decreasing |
| D. | Infinity |
| Answer» A. Maximum | |
| 135. |
The beam having one end free and one end fixed is called as |
| A. | Cantilever beam |
| B. | Continuous beam |
| C. | Overhang beam |
| D. | Simply supported beam |
| Answer» A. Cantilever beam | |
| 136. |
Uniformly varying load between two sections in shear force diagram is represented by |
| A. | cubic curve |
| B. | inclined line |
| C. | horizontal line |
| D. | parabolic curve |
| Answer» D. parabolic curve | |
| 137. |
In bending moment diagram, if no load acts between two sections, then it is represented by |
| A. | horizontal line |
| B. | inclined line |
| C. | vertical line |
| D. | all of the above |
| Answer» B. inclined line | |
| 138. |
What is the maximum bending moment acting on simply supported beam shown below? |
| A. | 2000 Nm |
| B. | 3000 Nm |
| C. | 4000 Nm |
| D. | 6000 Nm |
| Answer» D. 6000 Nm | |
| 139. |
A beam is said to be of uniform strength, if |
| A. | B.M. is same throughout the beam |
| B. | Shear stress is the same through the beam |
| C. | Deflection is the same throughout the beam |
| D. | Bending stress is the same at every section along its longitudinal axis |
| Answer» D. Bending stress is the same at every section along its longitudinal axis | |
| 140. |
What is the product of sectional modulus and allowable bending stress called as? |
| A. | Moment of inertia |
| B. | Moment of rigidity |
| C. | Moment of resistance |
| D. | Radius of gyration |
| Answer» C. Moment of resistance | |
| 141. |
A uniformly distributed load of 20 kN/m acts on a simply supported beam of rectangular cross section of width 20 mm and depth 60 mm. What is the maximum bending stress acting on the beam of 5m? |
| A. | 5030 Mpa |
| B. | 5208 Mpa |
| C. | 6600 Mpa |
| D. | Insufficient data |
| Answer» B. 5208 Mpa | |
| 142. |
Neutral axis of a beam always coincides with |
| A. | Axis passing through bottom of beam |
| B. | Axis passing through height h/2 from bottom |
| C. | Axis passing through height h/3 from bottom |
| D. | Axis passing through centroid |
| Answer» D. Axis passing through centroid | |
| 143. |
Net force acting on the cross section of beam in bending is |
| A. | Tensile |
| B. | Compressive |
| C. | Zero |
| D. | None |
| Answer» C. Zero | |
| 144. |
Net force acting on the cross section of beam in bending is |
| A. | Tensile |
| B. | Compressive |
| C. | Shear |
| D. | None |
| Answer» D. None | |
| 145. |
Which is more stronger in bending equal area square or circular beam |
| A. | Square beam |
| B. | Circular beam |
| C. | Both are equally strong |
| D. | None |
| Answer» B. Circular beam | |
| 146. |
Why is a composite beam is converted into a beam of one material |
| A. | Bending equation is applicable to one material beam |
| B. | Bending equation is applicable to one alloy beam |
| C. | Bending equation is applicable to one metal beam |
| D. | None |
| Answer» A. Bending equation is applicable to one material beam | |
| 147. |
Bending equation is applicable to a beam of |
| A. | Heterogeneous material |
| B. | Homogeneous material |
| C. | Alloy |
| D. | None |
| Answer» B. Homogeneous material | |
| 148. |
In a composite beam bending, strain at the common interface will be |
| A. | Equal |
| B. | Unequal |
| C. | Zero |
| D. | None |
| Answer» A. Equal | |
| 149. |
Brittle material beams need reinforcement on the |
| A. | Tension side |
| B. | Compression side |
| C. | Shear side |
| D. | None |
| Answer» A. Tension side | |
| 150. |
In bending, neutral axis always is |
| A. | Perpendicular to the centroidal axis |
| B. | Coincides with the centroidal axis |
| C. | Parallel to the centroidal axis |
| D. | None |
| Answer» B. Coincides with the centroidal axis | |
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