Who developed the BCNF?

Related MCQs

• If a relation is in BCNF, then it is also in
• R (A,B,C,D) is a relation. Which of the following does not have a lossless join dependency preserving BCNF decomposition?
• Relation R with an associated set of functional dependencies, F, is decomposed into BCNF. The redundancy (arising out of functional dependencies) in the resulting set of relations is
• A relation is in this form if it is in BCNF and has no multivalued dependencies:
• BCNF stands for:
• If a relation is in BCNF, then it is also in
• The normal form which satisfies multivalued dependencies and which is in BCNF is
• A relation is in this form if it is in BCNF and has no multivalued dependencies:
• If a relation scheme is in BCNF, then it is also in
• What is the expansion of BCNF?