A sinusoidal voltage of 5 Hz is applied to the field of a shunt generator. The armature voltage wave

Related MCQs

• The e.m.f. induced in the armature of a shunt generator is 600 V. The armature resistance is 0.1 ohm. If the armature current is 200 A, the terminal voltage will be
• Two generators A and B have 6-poles each. Generator A has wave wound armature while generator B has lap wound armature. The ratio of the induced e.m.f. is generatorA and B will be
• Two D.C. shunt generators, each with armature resistance of 0.02 ohm and field resistance of 50 ohm run in parallel and supply a total current of 1000 amperes to the load circuit. If their e.m.fs. are 270 V and 265 V, their bus bar voltage will be
• The e.m.f. generated by a shunt wound D.C. generator isE. Now while pole flux remains constant, if the speed of the generator is doubled, the e.m.f. generated will be
• If a D.C. shunt motor is working at no load and if shunt field circuit suddenly opens
• If a D.C. shunt motor is working at full load and if shunt field circuit suddenlyopens
• The series field of a short-shunt D.C. generator is excited by
• The terminal voltage of a D.C. shunt generator drops on load because of all of the following reasons except
• For given applied voltage, with the increase in frequency of the applied voltage
• The mechanical power developed by a shunt motor will be maximum when theratio of back e.m.f. to applied voltage is