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Adebowale

8 months ago

8086 Microprocessor Memory Segmentation CPU Architecture

How does the 8086 Microprocessor handle memory segmentation?

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6 Comments

Discussion

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David Purohit
8 months ago

The 8086 Microprocessor utilizes a segmentation model for memory management. It has a 20-bit address bus, allowing it to address up to 1MB of memory, but only has 16-bit registers. To access a memory location, an address is computed by combining a segment register and an offset register.

There are four main segment registers - CS (Code Segment), DS (Data Segment), SS (Stack Segment), and ES (Extra Segment) - each used for different types of memory access. The physical address is calculated by shifting the segment register 4 bits to the left (which essentially multiplies it by 16) and adding the offset.

The effective address, or logical address, given by:

PhysicalAddress = (SegmentRegister × 16) + Offset

This scheme allows for more flexibility, as one can use different segment-offset pairs to access the same physical memory location.

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Adebowale
8 months ago

Thank you for your detailed explanation on memory segmentation in the 8086 Microprocessor.
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SP

Satishwar Prabhakar
8 months ago

I appreciate the code snippet illustrating how the physical address is calculated. Handy for beginners!
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BHG

Binoya Himesh Goswami
8 months ago

Can you also elaborate on how the segment:offset pairs might point to the same physical address?
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AJ

Ademola Johnson
7 months ago

What are the implications of this model on programming in assembly language?
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UNR

Uma Natwar Ratta
7 months ago

Very concise explanation on the segment registers. Always found this a challenging concept!
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Adebayo
7 months ago

Is there a real-world example that can help understand the segmentation method better?
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