137
80.9k

980+ Material Science Solved MCQs

These multiple-choice questions (MCQs) are designed to enhance your knowledge and understanding in the following areas: Electrical Engineering .

151.

when the metal is stresses above its elastic limit, the resulting deformation is

A. permenant
B. temporary
C. partially permenant
D. a or c
Answer» D. a or c
152.

stress required during plastic deformation is than that required during elastic deformation

A. equal
B. high
C. low
D. b or c
Answer» B. high
153.

different shapes can be permentaly given to metals by virtue of property

A. elastic
B. plastic
C. none of the above
D. both a and b
Answer» B. plastic
154.

  mechannnial properties of the metal after plastic deformation

A. increases
B. either increase or decrease
C. remains constant
D. none of the above
Answer» B. either increase or decrease
155.

the plastic deformation can takes place through                 

A. slip
B. twinning
C. combination of slip and twinning
D. all of the above
Answer» D. all of the above
156.

slip is defined as displacement of one part of crystal relative to other

A. tensile
B. compressive
C. shear
D. bending
Answer» C. shear
157.

slip takes place due to                       

A. stress applied on material
B. chemical reaction within material
C. atmospheric reaction
D. none of the above
Answer» A. stress applied on material
158.

slip occurs along             plane and in direction

A. random, specific
B. specific, random
C. random, random
D. specific, specific
Answer» D. specific, specific
159.

the plane on which slip takes place is called plane

A. defective
B. imperfect
C. slip
D. twin
Answer» C. slip
160.

in slip, the crystal structure above and below the plane remains                        

A. distorted
B. undistorted
C. sometimes distorted
D. none of the above
Answer» B. undistorted
161.

slip occurs on plae which has                       

A. least number of atoms
B. random number of atoms
C. maximum number of atoms
D. no atoms
Answer» C. maximum number of atoms
162.

slip direction is direction in the slip plane which has                   

A. least number of atoms
B. random number of atoms
C. maximum number of atoms
D. no atoms
Answer» C. maximum number of atoms
163.

twin takes place due to                         

A. stress applied on material
B. chemical reaction within material
C. atmospheric reaction
D. none of the above
Answer» A. stress applied on material
164.

in twinning, the structure in the distorted region forms of the crystal structure in the distorted region

A. random orientation
B. mirror image
C. a or b
D. none of the above
Answer» B. mirror image
165.

the planes along which mirror image is formed is called planes

A. defective
B. imperfect
C. slip
D. twin
Answer» D. twin
166.

the plastic deformation takes place due to and                         

A. slip
B. twin
C. both of the above
D. none of the above
Answer» C. both of the above
167.

twining is the phenomenon observed due to                       

A. mechanical treatment
B. thermal treatment
C. chemical treatment
D. a or b
Answer» D. a or b
168.

metals are more ductile than metals

A. bcc,fcc
B. fcc,bcc
C. hcp,bcc
D. bcc,hcp
Answer» B. fcc,bcc
169.

generally metals with crystal structure are more ductile

A. bcc
B. fcc
C. hcp
D. a and c
Answer» B. fcc
170.

generally metals with crystal structure shows plastic deformation mainly by slip mechanism

A. bcc
B. fcc
C. hcp
D. a and c
Answer» D. a and c
171.

generally metals with crystal structure shows plastic deformation mainly by twinning mechanism

A. bcc
B. fcc
C. hcp
D. a and c
Answer» C. hcp
172.

twinning occurs along plane and direction

A. random, specific
B. specific, random
C. random, random
D. specific, specific
Answer» D. specific, specific
173.

               requires more stress to be initiated with respect to               

A. slip, twinning
B. twinning, slip
C. grain boundary defect, slip
D. none of the above
Answer» B. twinning, slip
174.

as compared to slip the stress required to propogate twin is                         

A. more
B. lesser
C. constant
D. varies randomly
Answer» B. lesser
175.

the appears as a pair of thick lines in the microscopic structure even after polishing

A. slip
B. twinning
C. combination of slip and twinning
D. all of the above
Answer» B. twinning
176.

The appears as a single thin line in the microscopic structure

A. slip
B. twinning
C. combination of slip and twinning
D. all of the above
Answer» A. slip
177.

the disappears after polishing

A. slip
B. twinning
C. combination of slip and twinning
D. all of the above
Answer» A. slip
178.

the can be seen in metal even after polishing

A. slip
B. twinning
C. combination of slip and twinning
D. all of the above
Answer» B. twinning
179.

the mechanism can be takes place due to thermal treatment

A. slip
B. twinning
C. combination of slip and twinning
D. all of the above
Answer» B. twinning
180.

metals with FCC crystal structure are often subjected to                           

A. slip
B. twinning
C. less of slip and more of twinning
D. all of the above
Answer» D. all of the above
181.

metals with FCC and BCC crystal structure are often subjected to

A. slip
B. twinning
C. combination of slip and twinning
D. all of the above
Answer» D. all of the above
182.

number of slip systems in metals decides about                       

A. hardness of metals
B. strength of metal
C. ductility of metal
D. all of the above
Answer» C. ductility of metal
183.

number of slip systems in FCC are

A. 12
B. 24
C. 21
D. 26
Answer» A. 12
184.

the law is used to determine the value of critical shear stress

A. millers
B. burgers
C. schmids
D. none of the above
Answer» C. schmids
185.

the schmids law is used to calculate critical shear stress for _                     structure

A. polycrystalli ne
B. single crystal
C. atoms
D. none of the above
Answer» B. single crystal
186.

the maximum resolved shear stress is given by                       

A. Ƭresolve = σt
B. Ƭresolve = σt/3
C. Ƭresolve = σt/2
D. none of the above
Answer» C. Ƭresolve = σt/2
187.

slip starts to occur when the value of resolved shear stress                       

A. reduces below critical shear stress
B. is at critical shear stress
C. increases abive critical shear stress
D. none of the above
Answer» C. increases abive critical shear stress
188.

FCC metals have value of critical shear stress as compared to BCC metals

A. same
B. lower
C. higher
D. random
Answer» B. lower
189.

FCC metals have higher ductility than BCC metals since _

A. fcc metals have higher
B. fcc metals have lower
C. fcc metals have lower
D. fcc metals have higher
Answer» B. fcc metals have lower
190.

the phenomenon by virtue of which metals become harder and stronger without any heat treatment is called

A. strain hardening
B. work hardening
C. all of the above
D. none of the above
Answer» C. all of the above
191.

after intial cold working, the stress required to further deform the material is

A. same
B. lower
C. higher
D. random
Answer» C. higher
192.

work hardening is the phenomenon observed if metal is worked the recrystallization temperature

A. above
B. below
C. independent of
D. none of the above
Answer» C. independent of
193.

working of metal below crystallization temperature is known as                               

A. cold working
B. hot working
C. any one of above
D. none of the above
Answer» A. cold working
194.

working of metal above crystallization temperature is known as                               

A. cold working
B. hot working
C. any one of above
D. none of the above
Answer» B. hot working
195.

for a given metal its recrystallization temperature depends on             

A. amonut of cold working
B. grain size
C. melting temperature s
D. all of the above
Answer» D. all of the above
196.

finer is the grain size -

A. more is recrystalliza tion temperature
B. lesser is the recrystalliza tion temperature
C. recrystalliza tion temperature remains same
D. none of the above
Answer» B. lesser is the recrystalliza tion temperature
197.

Frank-Reed source is associated with -

A. vacancy and interstitial defect
B. reductiion in dislocations
C. multiplicati on of dislocations
D. none of the above
Answer» C. multiplicati on of dislocations
198.

finer is the grain size -

A. more is dislocation density in cold working
B. lesser is dislocation density in cold working
C. dislocation density in cold working remains same
D. none of the above
Answer» A. more is dislocation density in cold working
199.

the mechanism of plastic deformation in polycrystalline material is than the mechanism in single crystal structure

A. simpler
B. complex
C. same
D. random
Answer» B. complex
200.

the stress required to produce same deformation is higher in case of                         polycrystalline material as compared to polycrystalline materials

A. coarse garined, fine grained
B. fine grained, coarse grained
C. a or b
D. none of the above
Answer» C. a or b

Done Studing? Take A Test.

Great job completing your study session! Now it's time to put your knowledge to the test. Challenge yourself, see how much you've learned, and identify areas for improvement. Don’t worry, this is all part of the journey to mastery. Ready for the next step? Take a quiz to solidify what you've just studied.