McqMate

1. |
## A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train? |

A. | 150 m |

B. | 120 m |

C. | 180 m |

D. | 200 m |

Answer» A. 150 m | |

Explanation: We know that, Distance = Speed * Time. Here, Distance is the length of the train and time = 9 seconds. We convert speed from km/hr to m/sec by multiplying by 5/18, so Speed = 60*(5/18) m/sec = 50/3 m/sec. Therefore, Distance = Speed * Time = 50/3 m/sec * 9 sec = 150 m. So, the length of the train is 150 m. |

2. |
## Two trains are moving in opposite directions at 60 km/hr and 90 km/hr. Their lengths are 1.2 km and 0.9 km respectively. How long will they take to cross each other? |

A. | 30.2 sec |

B. | 40.3 sec |

C. | 50.4 sec |

D. | 60.5 sec |

Answer» C. 50.4 sec | |

Explanation: Since the trains are moving in opposite directions, their relative speed is (60+90) km/hr = 150 km/hr. We convert this speed from km/hr to m/sec by multiplying by 5/18, so relative speed = 150*(5/18) m/sec = 125/3 m/sec. The total distance to be covered is the sum of the lengths of the two trains, which is 1.2 km + 0.9 km = 2.1 km = 2100 m. The time they take to cross each other is Distance/Speed = 2100 m / (125/3) m/sec = 50.4 sec. |

3. |
## A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform? |

A. | 200 m |

B. | 240 m |

C. | 280 m |

D. | 320 m |

Answer» B. 240 m | |

Explanation: The train's speed is 54 km/hr, which is 54*(5/18) m/sec = 15 m/sec. The length of the train is Speed * Time = 15 m/sec * 20 sec = 300 m. When the train crosses the platform, it travels the length of the train plus the length of the platform in 36 seconds. So, 300 m + length of platform = 15 m/sec * 36 sec. Solving for the platform's length gives the platform's length = 540 m - 300 m = 240 m. |

4. |
## Two trains of length 110 m and 90 m are running on parallel lines in the same direction at 45 km/hr and 30 km/hr respectively. In what time will the first train pass the second train? |

A. | 28 sec |

B. | 36 sec |

C. | 42 sec |

D. | 48 sec |

Answer» D. 48 sec | |

Explanation: The trains are moving in the same direction, so their relative speed is (45-30) km/hr = 15 km/hr. We convert this speed from km/hr to m/sec by multiplying by 5/18, so relative speed = 15*(5/18) m/sec = 25/6 m/sec. The first train will have to cover a distance equal to the sum of the lengths of the two trains to pass the second train completely, which is 110 m + 90 m = 200 m. So, the time taken = Distance/Speed = 200 m / (25/6) m/sec = 48 sec. |

5. |
## A train 240 m long passed a pole in 24 sec. How long will it take to pass a platform 650 m long? |

A. | 89 sec |

B. | 90 sec |

C. | 91 sec |

D. | 92 sec |

Answer» A. 89 sec | |

Explanation: The speed of the train is Distance/Time = 240 m / 24 sec = 10 m/sec. When the train crosses the platform, it travels the length of the train plus the length of the platform. So, the total distance = 240 m + 650 m = 890 m. Therefore, the time taken to cross the platform = Distance/Speed = 890 m / 10 m/sec = 89 sec. |

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