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| Q. |
An open tank containing liquid is made to move from rest with a uniform acceleration. The angle 0 which the free surface of liquid makes with the horizontal is such that (where a = Horizontal acceleration of the tank, and g = Acceleration due to gravity) |
| A. | tanθ = a/g |
| B. | tanθ = 2 a/g |
| C. | tanθ = a/2g |
| D. | tanθ = a2/2g |
| Answer» A. tanθ = a/g | |
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