

McqMate
Q. |
A 100 hp, 250 V, 350 A shunt dc motor with an armature resistance of 0.05 ohms. To limit maximum starting current to twice the rated of its value, what will be the number of stages of starting resistances? |
A. | 3 |
B. | 2 |
C. | 4 |
D. | 5 |
Answer» A. 3 | |
Explanation: n = log(ra/rt)/log(imin/imax); rt = vt/imax = 250/700 = 0.357 ohms |
View all MCQs in
Electrical Drives and Controls (EDC)No comments yet