Q.

In heat transfer, conductance equals conductivity (kcal/hr/sqm/°C/cm) divided by

A. hr (time)
B. sqm (area)
C. °C (temperature)
D. cm (thickness)
Answer» D. cm (thickness)
1.2k
0
Do you find this helpful?
6

View all MCQs in

Thermal Engineering 1

Discussion

No comments yet