#include<iostream>
using namespace std;
class Point {
public:
Point() { cout << "Constructor called"; }
};
int main()
{
Point t1, *t2;
return 0;
}

Related Questions

• Output of following program? #include <iostream> using namespace std; int fun(int=0, int = 0); int main() { cout << fun(5); return 0; } int fun(int x, int y) { return (x+y); }
• Output of the program? #include<iostream> using namespace std; int fun(int x = 0, int y = 0, int z) { return (x + y + z); } int main() { cout << fun(10); return 0; }
• Output of following C++ program? #include<iostream> using namespace std; int main() { int x = 10; int& ref = x; ref = 20; cout << "x = " << x << endl ; x = 30; cout << "ref = " << ref << endl; return 0; }
• Output of following program? #include<iostream> using namespace std; class Point { Point() { cout << "Constructor called"; } }; int main() { Point t1; return 0; }
• Predict the output? #include <iostream> using namespace std; class Test { int x; Test() { x = 5; } }; int main() { Test *t = new Test; cout << t->x; }
• Predict the output of following C++ program. #include<iostream> using namespace std; class Empty {}; int main() { cout << sizeof(Empty); return 0; }
• Is it fine to call delete twice for a pointer? #include<iostream> using namespace std; int main() { int *ptr = new int; delete ptr; delete ptr; return 0; }
• class Test { int x; }; int main() { Test t; cout << t.x; return 0; }
• Which of the following is true about pure virtual functions? 1) Their implementation is not provided in a class where they are declared. 2) If a class has a pure virtual function, then the class becomes abstract class and an instance of this class cannot be created.
• Implicit return type of a class constructor is: