Predict the output?
#include <iostream>
using namespace std;
class Test
{
int x;
Test()
{
x = 5;
} };
int main()
{
Test *t = new Test;
cout << t->x;
}

Related Questions

• Output of following program? #include <iostream> using namespace std; int fun(int=0, int = 0); int main() { cout << fun(5); return 0; } int fun(int x, int y) { return (x+y); }
• Output of the program? #include<iostream> using namespace std; int fun(int x = 0, int y = 0, int z) { return (x + y + z); } int main() { cout << fun(10); return 0; }
• Output of following C++ program? #include<iostream> using namespace std; int main() { int x = 10; int& ref = x; ref = 20; cout << "x = " << x << endl ; x = 30; cout << "ref = " << ref << endl; return 0; }
• Predict the output of following C++ program. #include<iostream> using namespace std; class Empty {}; int main() { cout << sizeof(Empty); return 0; }
• Output of following program? #include<iostream> using namespace std; class Point { Point() { cout << "Constructor called"; } }; int main() { Point t1; return 0; }
• Is it fine to call delete twice for a pointer? #include<iostream> using namespace std; int main() { int *ptr = new int; delete ptr; delete ptr; return 0; }
• #include<iostream> using namespace std; class Point { public: Point() { cout << "Constructor called"; } }; int main() { Point t1, *t2; return 0; }
• class Test { int x; }; int main() { Test t; cout << t.x; return 0; }
• Which of the following is true about pure virtual functions? 1) Their implementation is not provided in a class where they are declared. 2) If a class has a pure virtual function, then the class becomes abstract class and an instance of this class cannot be created.
• Which of the following is not correct (in C++)? 1. Class templates and function templates are instantiated in the same way 2. Class templates differ from function templates in the way they are initiated 3. Class template is initiated by defining an object using the template argument 4. Class templates are generally used for storage classes