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Q. |
What is the result of the recurrences which fall under the extended second case of Master’s theorem (let the recurrence be given by T(n)=aT(n/b)+f(n) and f(n)=nc(log n)k? |
A. | none of the below |
B. | t(n) = o(nc log n) |
C. | t(n)= o(nc (log n)k+1 |
D. | t(n) = o(n2) |
Answer» C. t(n)= o(nc (log n)k+1 | |
Explanation: in the extended second case of master’s theorem the necessary condition is that c = logba. if this condition is true then t(n)= o(nc(log n))k+1. |
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