McqMate
| Q. |
How many bits would be required to encode decimal numbers 0 to 9999 in straight binary codes? |
| A. | 12 |
| B. | 14 |
| C. | 16 |
| D. | 18 |
| Answer» B. 14 | |
| Explanation: total number of decimals to be represented = 10000 = 104 = 2n (where n is the number of bits required) = 213.29. therefore, the number of bits required for straight binary encoding = 14. | |
View all MCQs in
Digital Principles and System DesignNo comments yet