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Q. |
How many bits would be required to encode decimal numbers 0 to 9999 in straight binary codes? |
A. | 12 |
B. | 14 |
C. | 16 |
D. | 18 |
Answer» B. 14 | |
Explanation: total number of decimals to be represented = 10000 = 104 = 2n (where n is the number of bits required) = 213.29. therefore, the number of bits required for straight binary encoding = 14. |
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