McqMate
| Q. |
In the optical channel bandwidth is divided into non-overlapping frequency bands. |
| A. | time division multiplexing |
| B. | frequency division multiplexing |
| C. | code division multiplexing |
| D. | de-multiplexing |
| Answer» B. frequency division multiplexing | |
| Explanation: in fdm, the non-overlapping frequency bands are divided to the individual frequencies. these individual signals can be extracted from the combined fdm signal by electrical filtering at the receiver terminal. | |
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