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Q. |
Let the statement be “If n is not an odd integer then square of n is not odd.”, then if P(n) is “n is an not an odd integer” and Q(n) is “(square of n) is not odd.” For direct proof we should prove |
A. | ∀np ((n) → q(n)) |
B. | ∃ np ((n) → q(n)) |
C. | ∀n~(p ((n)) → q(n)) |
D. | ∀np ((n) → ~(q(n))) |
Answer» A. ∀np ((n) → q(n)) |
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