Q.

Let the statement be “If n is not an odd integer then square of n is not odd.”, then if P(n) is “n is an not an odd integer” and Q(n) is “(square of n) is not odd.” For direct proof we should prove                    

A. ∀np ((n) → q(n))
B. ∃ np ((n) → q(n))
C. ∀n~(p ((n)) → q(n))
D. ∀np ((n) → ~(q(n)))
Answer» A. ∀np ((n) → q(n))
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