McqMate
101. |
The principle objective of Sharpening, to highlight transitions is ___________________. |
A. | pixel density |
B. | composure |
C. | intensity |
D. | brightness |
Answer» C. intensity | |
Explanation: the principle objective of sharpening, to highlight transitions is intensity. |
102. |
How can Sharpening be achieved? |
A. | pixel averaging |
B. | slicing |
C. | correlation |
D. | none of the mentioned |
Answer» D. none of the mentioned | |
Explanation: sharpening is achieved using spatial differentiation. |
103. |
What does Image Differentiation enhance? |
A. | edges |
B. | pixel density |
C. | contours |
D. | none of the mentioned |
Answer» A. edges | |
Explanation: image differentiation enhances edges and other discontinuities. |
104. |
What does Image Differentiation de-emphasize? |
A. | pixel density |
B. | contours |
C. | areas with slowly varying intensities |
D. | none of the mentioned |
Answer» C. areas with slowly varying intensities | |
Explanation: image differentiation de-emphasizes areas with slowly varying intensities. |
105. |
The requirements of the First Derivative of a digital function: |
A. | must be zero in areas of constant intensity |
B. | must be non-zero at the onset of an intensity step |
C. | must be non-zero along ramps |
D. | all of the mentioned |
Answer» D. all of the mentioned | |
Explanation: all the three conditions must be satisfied. |
106. |
What is the Second Derivative of Image Sharpening called? |
A. | gaussian |
B. | laplacian |
C. | canny |
D. | none of the mentioned |
Answer» B. laplacian | |
Explanation: it is also called laplacian. |
107. |
The ability that rotating the image and applying the filter gives the same result, as applying the filter to the image first, and then rotating it, is called ______________________. |
A. | isotropic filtering |
B. | laplacian |
C. | rotation invariant |
D. | none of the mentioned |
Answer» C. rotation invariant | |
Explanation: it is called rotation invariant, although the process used is isotropic filtering. |
108. |
For a function f(x,y), the gradient of ‘f’ at coordinates (x,y) is defined as a ____________________. |
A. | 3-d row vector |
B. | 3-d column vector |
C. | 2-d row vector |
D. | 2-d column vector |
Answer» D. 2-d column vector | |
Explanation: the gradient is a 2-d column vector. |
109. |
Where do you find frequent use of Gradient? |
A. | industrial inspection |
B. | mri imaging |
C. | pet scan |
D. | none of the mentioned |
Answer» A. industrial inspection | |
Explanation: gradient is used in industrial inspection, to aid humans, in detection of defects. |
110. |
Which of the following occurs in Unsharp Masking? |
A. | blurring original image |
B. | adding a mask to original image |
C. | subtracting blurred image from original |
D. | all of the mentioned |
Answer» D. all of the mentioned | |
Explanation: in unsharp masking, all of the above occurs in the order: blurring, subtracting the blurred image and then adding the mask. |
111. |
Which of the following make an image difficult to enhance? |
A. | narrow range of intensity levels |
B. | dynamic range of intensity levels |
C. | high noise |
D. | all of the mentioned |
Answer» D. all of the mentioned | |
Explanation: all the mentioned options make it difficult to enhance an image. |
112. |
Which of the following is a second-order derivative operator? |
A. | histogram |
B. | laplacian |
C. | gaussian |
D. | none of the mentioned |
Answer» B. laplacian | |
Explanation: laplacian is a second-order derivative operator. |
113. |
Response of the gradient to noise and fine detail is _____________ the Laplacian’s. |
A. | equal to |
B. | lower than |
C. | greater than |
D. | has no relation with |
Answer» B. lower than | |
Explanation: response of the gradient to noise and fine detail is lower than the laplacian’s and can further be lowered by smoothing. |
114. |
Dark characteristics in an image are better solved using ____________________. |
A. | laplacian transform |
B. | gaussian transform |
C. | histogram specification |
D. | power-law transformation |
Answer» D. power-law transformation | |
Explanation: it can be solved by histogram specification but it is better handled by power-law transformation. |
115. |
What is the smallest possible value of a gradient image? |
A. | e |
B. | 1 |
C. | 0 |
D. | -e |
Answer» C. 0 | |
Explanation: the smallest possible value of a gradient image is 0. |
116. |
Which of the following fails to work on dark intensity distributions? |
A. | laplacian transform |
B. | gaussian transform |
C. | histogram equalization |
D. | power-law transformation |
Answer» C. histogram equalization | |
Explanation: histogram equalization fails to work on dark intensity distributions. |
117. |
_________________________ is used to detect diseases such as bone infection and tumors. |
A. | mri scan |
B. | pet scan |
C. | nuclear whole body scan |
D. | x-ray |
Answer» C. nuclear whole body scan | |
Explanation: nuclear whole body scan is used to detect diseases such as bone infection and tumors |
118. |
How do you bring out more of the skeletal detail from a Nuclear Whole Body Bone Scan? |
A. | sharpening |
B. | enhancing |
C. | transformation |
D. | none of the mentioned |
Answer» A. sharpening | |
Explanation: sharpening is used to bring out more of the skeletal detail. |
119. |
Final step of enhancement lies in ________________ of the sharpened image. |
A. | increase range of contrast |
B. | increase range of brightness |
C. | increase dynamic range |
D. | none of the mentioned |
Answer» C. increase dynamic range | |
Explanation: increasing the dynamic range of the sharpened image is the final step in enhancement. |
120. |
An alternate approach to median filtering is ______________ |
A. | use a mask |
B. | gaussian filter |
C. | sharpening |
D. | laplacian filter |
Answer» A. use a mask | |
Explanation: using a mask, formed from the smoothed version of the gradient image, can be used for median filtering. |
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