McqMate
Q. |
The time taken by all-to- all broadcast on a hypercube is . |
A. | t= (ts + twm)(p-1) |
B. | t= ts logp + twm(p-1) |
C. | t= 2ts(√p – 1) - twm(p-1) |
D. | t= 2ts(√p – 1) + twm(p-1) |
Answer» C. t= 2ts(√p – 1) - twm(p-1) |
View all MCQs in
High Performance Computing (HPC)No comments yet