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Q. |
The time taken by all-to- all broadcast on a mesh is . |
A. | t= (ts + twm)(p-1) |
B. | t= ts logp + twm(p-1) |
C. | t= 2ts(√p – 1) - twm(p-1) |
D. | t= 2ts(√p – 1) + twm(p-1) |
Answer» A. t= (ts + twm)(p-1) |
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