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| Q. |
In a push - pull converter, the filter capacitor can be obtained as |
| A. | Cmin = V / ( Vr L f2 ) |
| B. | Cmin= ( 1 – D ) V / ( Vr L f2 ) |
| C. | Cmin= ( 1 – 2 D ) V / 32 ( Vr L f2 ) |
| D. | Cmin= ( 1 – 2 D ) V / 42 ( Vr L f2 ) |
| Answer» C. Cmin= ( 1 – 2 D ) V / 32 ( Vr L f2 ) | |
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