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| Q. |
If the moment of inertia of a section about its axis is and its effective sectional area is, its radius of gyration r about the axis, is |
| A. | r = I/A |
| B. | r I/A) |
| C. | r = (I/A) |
| D. | r A/I) |
| Answer» B. r I/A) | |
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