Q.

If the moment of inertia of a section about its axis is and its effective sectional area is , its radius of gyration r about the axis, is

A. r = i/a
B. r i/a)
C. r = (i/a)
D. r a/i)
Answer» B. r i/a)
3.5k
0
Do you find this helpful?
21

Discussion

No comments yet

Related MCQs