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| Q. |
If the moment of inertia of a section about its axis is and its effective sectional area is , its radius of gyration r about the axis, is |
| A. | r = i/a |
| B. | r i/a) |
| C. | r = (i/a) |
| D. | r a/i) |
| Answer» B. r i/a) | |
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