A particle is moving in Simple Harmonic Motion in a simple pendulum with some period of oscillation. Now in order to double the period of oscillation

Related MCQs

• The moving parts of a machine which weigh 1 tonne perform vertical simple harmonic motion with an amplitude of 2.5 cm and a period of 0.5 sec. The base of the machine weighs 3 tonnes and rests on the ground. Maximum reactions on the ground would be
• A particle in simple Harmonic Motion while passing through mean position will have
• The periodic time of a body moving in Simple Harmonic Motion is
• A particle moves along a rough plane inclined at 30? to the horizontal. The co-efficient of friction between the particle and the plane is 0.1. Its initial velocity is 15 m/sec. The ratio of the velocity of the particle when it move down the plane to that when it move up the plane would be in the regions
• A body is vibrating with simple harmonic motion of aplitude 5 cm frequency 10 vibrations per second. The maximum value of velocity in cm/s will be
• A body is executing simple harmonic motion of amplitude 1 cm. Its velocitywhile passing through the central point is 10 mm/sec. Its frequency will be
• A body in Simple Harmonic Motion will attain maximum velocity when it passes through
• A particle starts from rest and moves in a straight line whose equation of motion is given by S = 2t3 - t2 - 1. The acceleration of the particle after one sec will be
• A bob of simple pendulum oscillating in air is made to oscillate in oil. The time period will
• If air resistance is neglected, at the mid-point of its swing, the acceleration of the bob of a simple pendulum along its path is always