Q.

In ultimate analysis, %hydrogen is given by                      

A. (increase in weight of cacl2 tube×2×100 / weight of coal sample taken×18)
B. (increase in weight of koh tube×2×100 / weight of coal sample taken×18)
C. (increase in weight of cacl2 tube×4×100 / weight of coal sample taken×18)
D. (increase in weight of koh tube×4×100 / weight of coal sample taken×18)
Answer» A. (increase in weight of cacl2 tube×2×100 / weight of coal sample taken×18)
Explanation: %hydrogen= (weight of hydrogen/weight of coal sample taken) × 100 in ultimate analysis of coal,
2.9k
0
Do you find this helpful?
39

View all MCQs in

Engineering Chemistry

Discussion

No comments yet