Q.

If 1/h12 = 4, for a C.E. stage- what is the value of the base to collector capacitance, after Miller multiplication, at the input side?

A. 4cµ
B. 5cµ
C. 6cµ
D. 1.1cµ
Answer» C. 6cµ
Explanation: the capacitor, cµ, gets multiplied by a factor of (1 + av), at the input side of a c.e. stage. 1/h12 is equal to av since h12 is the reverse voltage amplification factor. hence, the final value becomes 5cµ.
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