Efficiency of a centre tapped full wave rectifier is                    

Related MCQs

• In a centre tapped full wave rectifier, RL=1KΩ and for diode Rf=10Ω. The primary voltage is 800sinωt with transformer turns ratio=2. The ripple factor will be                    
• If the peak voltage on a centre tapped full wave rectifier circuit is 5V and diode cut in voltage is 0.7. The peak inverse voltage on diode is
• In a half wave rectifier, the sine wave input is 50sin50t. If the load resistance is of 1K, then average DC power output will be?
• Efficiency of a half wave rectifier is
• A full wave rectifier delivers 50W to a load of 200Ω. If the ripple factor is 2%, calculate the AC ripple across the load.
• The diode in a half wave rectifier has a forward resistance RF. The voltage is Vmsinωt and the load resistance is RL. The DC current is given by                    
• If peak voltage for a half wave rectifier circuit is 5V and diode cut in voltage is 0.7, then peak inverse voltage on diode will be?
• Transformer utilisation factor of a half wave rectifier is                    
• If the input frequency of a half wave rectifier is 100Hz, then the ripple frequency will be                   
• Due to centre tap Vm=400/2=200) IRMS=198/√2=140mA, IAVG=2*198/ π=126mA. ϒ=[(140/126)2-1]1/2=0.48. So, ϒ=48%.