Q.

In a centre tapped full wave rectifier, RL=1KΩ and for diode Rf=10Ω. The primary voltage is 800sinωt with transformer turns ratio=2. The ripple factor will be                    

A. 54%
B. 48%
C. 26%
D. 81%
Answer» B. 48%
Explanation: the ripple factor ϒ= [(irms/iavg)2 – 1]1/2. irms =im /
1.6k
0
Do you find this helpful?
13

View all MCQs in

Electronic Circuits 1

Discussion

No comments yet