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Q. |
A point in 4th quadrant is 8 inches away from the horizontal plane and 20 inches away from both the vertical plane and profile plane. Orthographic projections are drawn find the distance from side view and top view. |
A. | 41.76 |
B. | 20 |
C. | 43.08 |
D. | 16 |
Answer» A. 41.76 | |
Explanation: given the point is in the 4th quadrant. since here distance from side view and top view is asked for that we need the distance between the front view and side view (20+20); front view and top view (20-8) and these lines which form perpendicular to each other gives needed distance, answer is |
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