A point in 2nd quadrant is 25 units away from both the horizontal plane and profile plane 15 units away from the vertical plane. Orthographic projections are drawn find the distance from the side view and top view.
|Answer» D. 41.23|
|Explanation: given the point is in 2nd quadrant. since here distance from side view and top view is asked for that we need the distance between the front view and side view (25+15); front view and top view (25-15) and these lines which form perpendicular to each other gives needed distance, answer is|
Login to Continue
It will take less than 2 minutes