McqMate
These multiple-choice questions (MCQs) are designed to enhance your knowledge and understanding in the following areas: Electronics and Telecommunication Engineering [ENTC] .
| 151. |
Rectangular crosspoint array is a |
| A. | Space switching |
| B. | Electronic switching |
| C. | Digital switching |
| D. | Time switching |
| Answer» A. Space switching | |
| 152. |
A time division time switch can be controlled in |
| A. | Sequential write/random read |
| B. | random write/random read |
| C. | random write/sequential read |
| D. | All of above |
| Answer» D. All of above | |
| 153. |
In a one-stage space division switch, if N = 200, the number of cross points is |
| A. | 10,000 |
| B. | 20,000 |
| C. | 40,000 |
| D. | 30,000 |
| Answer» C. 40,000 | |
| 154. |
ESS stands for |
| A. | Electronic Switching System |
| B. | Effective Electronic Switching System |
| C. | Early Electronic Switching System |
| D. | none of these. |
| Answer» A. Electronic Switching System | |
| 155. |
Circuit switching takes place at the layer of |
| A. | data line |
| B. | physical |
| C. | network |
| D. | transport |
| Answer» B. physical | |
| 156. |
Trunks are the lines that run between |
| A. | switching system and power plant |
| B. | Local area network |
| C. | Switching stations |
| D. | Subscribers and exchange |
| Answer» C. Switching stations | |
| 157. |
Availability of single processor system is given by |
| A. | MTBF/MTTR |
| B. | MTTR/MTBF |
| C. | MTTR/(MTBF+MTTR) |
| D. | MTBF/(MTBF+MTTR) |
| Answer» D. MTBF/(MTBF+MTTR) | |
| 158. |
Unavailability of single processor system is given by |
| A. | MTBF/MTTR |
| B. | MTTR/MTBF |
| C. | MTTR/(MTBF+MTTR) |
| D. | MTBF/(MTBF+MTTR) |
| Answer» B. MTTR/MTBF | |
| 159. |
Availability of Dual processor system is given by |
| A. | MTBF2/MTTR2 |
| B. | 2MTTR/MTBF2 |
| C. | MTTR2/2(MTBF+MTTR)2 |
| D. | (MTBF)2/(MTBF)2+2(MTTR)2 |
| Answer» D. (MTBF)2/(MTBF)2+2(MTTR)2 | |
| 160. |
Unavailability of Dual processor system is given by |
| A. | MTBF2/MTTR2 |
| B. | 2MTTR2/MTBF2 |
| C. | 2MTTR2/2(MTBF+MTTR)2 |
| D. | (MTBF)2/(MTBF)2+2(MTTR)2 |
| Answer» B. 2MTTR2/MTBF2 | |
| 161. |
Who developed the fundamental of trunking theory? |
| A. | Newton |
| B. | Ohm |
| C. | Erlang |
| D. | Einstein |
| Answer» C. Erlang | |
| 162. |
MTTR means |
| A. | Maximum Time To Repair |
| B. | Most Time To Repair |
| C. | Mean Time To Repair. |
| D. | Maximum Time To Repair |
| Answer» C. Mean Time To Repair. | |
| 163. |
Which form/s of grading design has/have the tendency to share every trunk between equal numbers of groups? |
| A. | Homogeneous Grading |
| B. | Heterogeneous Grading |
| C. | Skipped Grading |
| D. | All of the above |
| Answer» A. Homogeneous Grading | |
| 164. |
In a time multiplexed space switching system, one speech sample appears every |
| A. | 125 micro sec |
| B. | 20 msec |
| C. | 125 msec |
| D. | 1 sec |
| Answer» A. 125 micro sec | |
| 165. |
Time synchronization is necessary in |
| A. | FDM |
| B. | TDM |
| C. | WDM |
| D. | Quadrature multiplexing |
| Answer» B. TDM | |
| 166. |
Three methods of switching are |
| A. | circuit switching, packet switching, and protocol switching |
| B. | circuit switching, packet switching, and message switching |
| C. | Loop switching, packet switching, and message switching |
| D. | Node switching, packet switching, and message switching |
| Answer» B. circuit switching, packet switching, and message switching | |
| 167. |
If ‘n’ number of users are present in a network with point-to-point links, then how many links will be required in the network? |
| A. | n (n – 1) |
| B. | n (n – 1) / 2 |
| C. | n (n – 1) / 4 |
| D. | n (n – 1) / 8 |
| Answer» B. n (n – 1) / 2 | |
| 168. |
Which among the following is/are adopted by cross bar systems with hard wired control subsystem? |
| A. | Relays |
| B. | Latches |
| C. | Both a and b |
| D. | None of the above |
| Answer» C. Both a and b | |
| 169. |
What is the hardware, used to establish connection as an electrical path between inlet and outlet pair in switching system, known as? |
| A. | Switching Matrix |
| B. | Switching Network |
| C. | Both a and b |
| D. | None of the above |
| Answer» C. Both a and b | |
| 170. |
In folded type of network, ____ |
| A. | input lines are folded back to output lines |
| B. | output lines are folded back to input lines |
| C. | input lines are folded back to themselves (input lines) |
| D. | output lines are folded back to themselves (output lines) |
| Answer» B. output lines are folded back to input lines | |
| 171. |
For the two-group grading consisting of 14 trunks, availability = 5, Ak = 1.4E and the required grade of service of about 0.01, what would be its traffic capacity? |
| A. | 4.98 E |
| B. | 6.72 E |
| C. | 8.3 E |
| D. | 10 E |
| Answer» A. 4.98 E | |
| 172. |
Which kind of switching system does not comprise any subscriber, concentrator or expander? |
| A. | Crossbar |
| B. | Director Exchange |
| C. | Strowger |
| D. | Tandem |
| Answer» D. Tandem | |
| 173. |
In Electronic Switching Centre (ESC), the transmission rate of X.25 protocol is ____9.6 Kbps. |
| A. | Less than |
| B. | Equal to |
| C. | Greater than |
| D. | None of the above |
| Answer» C. Greater than | |
| 174. |
In a single stage network |
| A. | There is no redundancy |
| B. | There is redundancy |
| C. | Alternative cross points are available |
| D. | Alternative paths are available |
| Answer» B. There is redundancy | |
| 175. |
What are the Methods to move data through a network of links and switches |
| A. | Packet switching |
| B. | Circuit switching |
| C. | Line switching |
| D. | Both a and b |
| Answer» D. Both a and b | |
| 176. |
In _________ resources are allocated on demand. |
| A. | Packet switching |
| B. | circuit switching |
| C. | line switching |
| D. | frequency switching |
| Answer» A. Packet switching | |
| 177. |
The situation when both transmitter and receiver have to work in tandem is referred to as |
| A. | Parallel |
| B. | Serial |
| C. | Synchronous |
| D. | Asynchronous |
| Answer» C. Synchronous | |
| 178. |
Given that MTBF=2000Hrs and MTTR = 4Hrs. Calculate the unavailability for single processor systems for 10 years and 30 years. |
| A. | For 10years: U=175.2Hrs and For 30 Years, U=525.6 Hrs. |
| B. | For 10years: U=180.2Hrs and For 30 Years, U=500.6 Hrs. |
| C. | For 10years: U=195.2Hrs and For 30 Years, U=550.6 Hrs. |
| D. | None of the above |
| Answer» A. For 10years: U=175.2Hrs and For 30 Years, U=525.6 Hrs. | |
| 179. |
Given that MTBF=2000Hrs and MTTR = 4Hrs. Calculate the unavailability for dual processor systems for 10 years and 30 years. |
| A. | For 10years: U=40.04 min and For 30 Years, U=2.1 Hrs. |
| B. | For 10years: U=180.2Hrs and For 30 Years, U=500.6 Hrs. |
| C. | For 10years: U=195.2Hrs and For 30 Years, U=550.6 Hrs. |
| D. | None of the above |
| Answer» A. For 10years: U=40.04 min and For 30 Years, U=2.1 Hrs. | |
| 180. |
Dual processor operates in ____ modes |
| A. | Standby |
| B. | Synchronous |
| C. | Load Sharing |
| D. | All of the above |
| Answer» D. All of the above | |
| 181. |
Total number of crosspoints in the two stage concentrator network |
| A. | C2=2/M1/2 N |
| B. | C2=2/N1/2 M |
| C. | C2=2N/(M+N)1/2 |
| D. | C2=2M/(M+N)1/2 |
| Answer» A. C2=2/M1/2 N | |
| 182. |
Total number of crosspoints in the two stage Expander network |
| A. | C2=2/M1/2 N |
| B. | C2=2/N1/2 M |
| C. | C2=2N/(M+N)1/2 |
| D. | C2=2M/(M+N)1/2 |
| Answer» B. C2=2/N1/2 M | |
| 183. |
Total number of crosspoints in the three stage concentrator network |
| A. | C3=2/M1/2 N |
| B. | C3=2/N1/2 M |
| C. | C3=2N/(M+N)1/2 |
| D. | C3=2M/(M+N)1/2 |
| Answer» C. C3=2N/(M+N)1/2 | |
| 184. |
Total number of crosspoints in the three stage expander network |
| A. | C3=2/M1/2 N |
| B. | C3=2/N1/2 M |
| C. | C3=2N/(M+N)1/2 |
| D. | C3=2M/(M+N)1/2 |
| Answer» D. C3=2M/(M+N)1/2 | |
| 185. |
Number of inlets and outlets in the two stage concentrator network are given by the formula |
| A. | m = n= M1/2 |
| B. | m = n= N1/2 |
| C. | m = M/ (M+N)1/2 , n = N/ (M+N)1/2 |
| D. | All of the above |
| Answer» A. m = n= M1/2 | |
| 186. |
Number of inlets and outlets in the two stage Expander network are given by the formula |
| A. | m = n= M1/2 |
| B. | m = n= N1/2 |
| C. | m = M/ (M+N)1/2 , n = N/ (M+N)1/2 |
| D. | All of the above |
| Answer» B. m = n= N1/2 | |
| 187. |
Different forms of grading are |
| A. | Skipped, Homogeneous, progressive |
| B. | Skipped, sequential, progressive |
| C. | Skipped, Homogeneous, random |
| D. | None of the above |
| Answer» A. Skipped, Homogeneous, progressive | |
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