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600+ Digital Electronics and Logic Design Solved MCQs

These multiple-choice questions (MCQs) are designed to enhance your knowledge and understanding in the following areas: Computer Science Engineering (CSE) , Electronics and Telecommunication Engineering [ENTC] .

1.

The 2s compliment form (Use 6 bit word) of the number 1010 is

A. 111100
B. 110110
C. 110111
D. 1011
Answer» B. 110110
2.

AB+(A+B)’ is equivalent to

A. a ex-nor b
B. a ex or b
C. (a+b)a
D. (a+b)b
Answer» A. a ex-nor b
3.

The hexadecimal number equivalent to (1762.46)8 is

A. 3f2.89
B. 3f2.98
C. 2f3.89
D. 2f3.98
Answer» B. 3f2.98
4.

A three input NOR gate gives logic high output only when

A. one input is high
B. one input is low
C. two input are low
D. all input are low
Answer» D. all input are low
5.

The absorption law in Boolean algebra say that

A. x + x = x
B. x . y = x
C. x + x . y = x
D. none of the above
Answer» C. x + x . y = x
6.

Logic X-OR operation of (4ACO)H & (B53F)H results

A. aacb
B. 0
C. abcd
D. ffff
Answer» D. ffff
7.

What is decimal equivalent of (11011.1000)2 ?

A. 22
B. 22.2
C. 20.2
D. 27.5
Answer» D. 27.5
8.

The negative numbers in the binary system can be represented by

A. sign magnitude
B. 2\s complement
C. 1\s complement
D. all of the above
Answer» D. all of the above
9.

Negative numbers cannot be represented in

A. signed magnitude form
B. 1’s complement form
C. 2’s complement form
D. none of the above
Answer» D. none of the above
10.

The answer of the operation (10111)2*(1110)2 in hex equivalence is

A. 150
B. 241
C. 142
D. 1.01e+08
Answer» C. 142
11.

The Hexadecimal number equivalent of (4057.06)8 is

A. 82f.027
B. 82f.014
C. 82f.937
D. 83f.014
Answer» B. 82f.014
12.

The NAND gate output will be low if the two inputs are

A. 0
B. 1
C. 10
D. 11
Answer» D. 11
13.

A binary digit is called a

A. bit
B. character
C. number
D. byte
Answer» A. bit
14.

What is the binary equivalent of the decimal number 368

A. 101110000
B. 110110000
C. 111010000
D. 1.11e+08
Answer» A. 101110000
15.

What is the binary equivalent of the Octal number 367

A. 11110111
B. 11100111
C. 110001101
D. 10111011 1
Answer» A. 11110111
16.

What is the binary equivalent of the Hexadecimal number 368

A. 1111101000
B. 1101101000
C. 1101111000
D. 1.11e+09
Answer» B. 1101101000
17.

What is the binary equivalent of the decimal number 1011

A. 1111110111
B. 1111000111
C. 1111110011
D. 1.11e+09
Answer» C. 1111110011
18.

The gray code equivalent of (1011)2 is

A. 1101
B. 1010
C. 1111
D. 1110
Answer» D. 1110
19.

The decimal equivalent of hex number 1A53 is

A. 6793
B. 6739
C. 6973
D. 6379
Answer» B. 6739
20.

( 734)8 =( )16

A. c 1 d
B. d c 1
C. 1 c d
D. 1 d c
Answer» D. 1 d c
21.

The simplification of the Boolean expression (A'BC')'+ (AB'C)' is

A. 0
B. 1
C. a
D. bc
Answer» B. 1
22.

The hexadecimal number ‘A0’ has the decimal value equivalent to

A. 80
B. 256
C. 100
D. 160
Answer» D. 160
23.

The Boolean expression A.B+ A.B+ A.B is equivalent to

A. a + b
B. a\.b
C. (a + b)\
D. a.b
Answer» A. a + b
24.

The 2’s complement of the number 1101101 is

A. 101110
B. 111110
C. 110010
D. 10011
Answer» D. 10011
25.

When simplified with Boolean Algebra (x + y)(x + z) simplifies to

A. x
B. x + x(y + z)
C. x(1 + yz)
D. x + yz
Answer» D. x + yz
26.

The code where all successive numbers differ from their preceding number by single bit is

A. binary code.
B. bcd.
C. excess – 3.
D. gray.
Answer» D. gray.
27.

-8 is equal to signed binary number

A. 10001000
B. oooo1000
C. 10000000
D. 11000000
Answer» A. 10001000
28.

DeMorgan’s first theorem shows the equivalence of

A. or gate and exclusive or gate.
B. nor gate and bubbled and gate.
C. nor gate and nand gate.
D. nand gate and not gate
Answer» B. nor gate and bubbled and gate.
29.

When signed numbers are used in binary arithmetic, then which one of the following notations would have unique representation for zero.

A. sign- magnitude.
B. 1’s complement.
C. 2’s complement.
D. 9’s compleme nt.
Answer» A. sign- magnitude.
30.

The decimal equivalent of Binary number 11010 is

A. 26
B. 36
C. 16
D. 23
Answer» A. 26
31.

1’s complement representation of decimal number of -17 by using 8 bit

A. 1110 1110
B. 1101 1101
C. 1100 1100
D. 0001 0001
Answer» A. 1110 1110
32.

The excess 3 code of decimal number 26 is

A. 0100 1001
B. 1011001
C. 1000 1001
D. 1001101
Answer» B. 1011001
33.

How many AND gates are required to realize Y = CD+EF+G

A. 4
B. 5
C. 3
D. 2
Answer» D. 2
34.

The hexadecimal number for (95.5)10 is

A. (5f.8) 16
B. (9a.b) 16
C. ( 2e.f) 16
D. ( 5a.4) 16
Answer» A. (5f.8) 16
35.

The octal equivalent of (247) 10 is

A. ( 252) 8
B. (350) 8
C. ( 367) 8
D. ( 400) 8
Answer» C. ( 367) 8
36.

The number 140 in octal is equivalent to

A. (96)10 .
B. ( 86) 10
C. (90) 10 .
D. none of these.
Answer» A. (96)10 .
37.

The NOR gate output will be low if the two inputs are

A. 11
B. 1
C. 10
D. all
Answer» D. all
38.

Convert decimal 153 to octal. Equivalent in octal will be

A. (231)8
B. ( 331) 8
C. ( 431) 8 .
D. none of these.
Answer» A. (231)8
39.

The decimal equivalent of ( 1100)2 is

A. 12
B. 16
C. 18
D. 20
Answer» A. 12
40.

The binary equivalent of (FA)16 is

A. 1010 1111
B. 1111 1010
C. 10110011
D. none of these
Answer» B. 1111 1010
41.

How many two-input AND and OR gates are required to realize Y=CD+EF+G

A. 22
B. 23
C. 33
D. none of these
Answer» A. 22
42.

The excess-3 code of decimal 7 is represented by

A. 1100
B. 1001
C. 1011
D. 1010
Answer» D. 1010
43.

When an input signal A=11001 is applied to a NOT gate serially, its output signal is

A. 111
B. 110
C. 10101
D. 11001
Answer» B. 110
44.

The result of adding hexadecimal number A6 to 3A is

A. dd
B. e0
C. f0
D. ef
Answer» B. e0
45.

A universal logic gate is one, which can be used to generate any logic function. Which of the following is a universal logic gate?

A. or
B. and
C. xor
D. nand
Answer» D. nand
46.

Karnaugh map is used for the purpose of

A. reducing the electronic circuits used.
B. to map the given boolean logic function.
C. to minimize the terms in a boolean expression.
D. to maximize the terms of a given a boolean expression .
Answer» C. to minimize the terms in a boolean expression.
47.

The 2’s complement of the number 1101110 is

A. 10001
B. 10001
C. 10010
D. none
Answer» C. 10010
48.

The decimal equivalent of Binary number 10101 is

A. 21
B. 31
C. 26
D. 28
Answer» A. 21
49.

How many two input AND gates and two input OR gates are required to realize Y = BD+CE+AB

A. 11
B. 42
C. 32
D. 23
Answer» C. 32
50.

Which of following are known as universal gates

A. nand & nor
B. and & or.
C. xor & or.
D. none.
Answer» A. nand & nor

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