What type of magnetization uses the formula: I = 45000/(L/D)N where I is the current in Amperes, N the number of turns of the magnetizing coil, L the length of the cylindrical test piece and D its diameter.

Related MCQs

• How many turns of a coil will be needed to establish a longitudinal field in a steel shaft that is 22.86 cm (9 inches) long and 7.62 cm (3 inches) in diameter? 3000 amperes magnetizing current is available, it is desired to magnetize the part in accordance with the formula NI = 45,000/(L/D):
• When using a straight beam technique to examine a thick test piece what change(s) would you expect to see in back wall echo size as you approach the side of the test piece? (Transducer remains completely on test piece)
• According to ASTM E709-95, with wet continuous magnetization technique, the duration of magnetization current is of the order of:
• The formula, NI = 45000/(L/D), gives proper magnetising current for a coil, regardless of coil size as long as:
• In which magnetizing method is the current passed directly through the part, thereby setting up a magnetic field at right angles to the current flow?
• According to ASTM E709-95 in using prods having a spacing of 19 mm (3/4 inches) and above, the magnetizing current shall be:
• Demagnetization, ASTM E709-95 recommends a coil of ampere-turns:
• A soft aluminium test piece is to be penetrant tested. The piece has previously been sand blasted to remove tightly adhering soils. What additional surface preparation should be performed?
• The proper number of ampere-turns for a given test specimen is determined by:
• The correct number of ampere-turns for a given test specimen is determined by: