According to the method of images, the tangential component of electric field to conductor surface is __________.

Related MCQs

• "The surface integral of the normal component of the electric displacement D over any closed surface equals the charge enclosed by the surface". The above statement is associated with
• The electric field at a point situated as a distance d from straight charged conductor is
• The electric field at a point situated at a distance d from straight charged conductor is
• The direction of electric dipole moment is _________ applied electric field.
• Electric intensity at any point in an electric field is equal to the at that point.
• For those surfaces where surface charge density is __________ normal component of electric flux density is continuous.
• The electric field intensity at a point situated at 4 meters away from a point charge 200 N/C. if the distance is reduced to 2 meters, the field intensity will be.
• The electric field intensity at a point situated 4 metres from a point charge is 200 N/C. If the distance is reduced to 2 metres, the field intensity will be
• The number of Faraday tubes of flux passing through a surface in an electric field is called
• Electrostatic field is _________ a perfect conductor.