Q.

What is the percent composition of a mixture of (S)-(+)-2-butanol, α= +13.52°, and (R)-(-)-2-butanol, α = -13.52°, with a specific rotation α = +6.76°?

A. 75%(R) 25%(S)
B. 25%(R) 75%(S)
C. 50%(R) 50%(S)
D. 67%(R) 33%(S)
Answer» A. 75%(R) 25%(S)
639
0
Do you find this helpful?
0

Discussion

No comments yet