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Q. |
flat foot step bearing 20 cm in diameter supports a load of 2500 kgf. The shaft is running at 420 rpm and the co-efficient is 0.09. The power transmitted by the friction between the surface, will be equal to ___. |
A. | 493.875 watt |
B. | 880 watt |
C. | 659.7 watt |
D. | 680.20 watt |
Answer» A. 493.875 watt |
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