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Q. |
## A flat foot step bearing 20 cm in diameter supports a load of 2500 kgf. The shaft is running at 420 rpm and the co-efficient is 0.09. The power lost in overcoming friction at the bearing, will be equal to ___. |

A. | 650 watt |

B. | 880 watt |

C. | 659.7 watt |

D. | 680.20 watt |

Answer» C. 659.7 watt |

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