The shear stress required to cause plastic deformation of solid metals is known as

Related MCQs

• Whenever some external system of forces acts on a body, it undergoes some deformation. As the body undergoes some deformation, it sets up some resistance to the deformation. This resistance per unit area to deformation, is called
• A body is subjected to a tensile stress of 1200 MPa on one plane and another tensile stress of 600 MPa on a plane at right angles to the former. It is also subjected to a shear stress of 400 MPa on the same planes. The maximum normal stress will be
• At a point in a steel member, the major principal stress is 2000 kg/cm2 and the minor principal stress is compressive. If the uni-axial tensile yield stress is 2500 kg/cm2, then the magnitude of the minor principal stress at which yielding will commence, according to the maximum shearing stress theory, is
• A shear stress across a plane, is always accompanied by a balancing shear stress across the plane and normal to it.
• The ratio of maximum shear stress to average shear stress in case of a circular beam transmitting power is equal to
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• The ratio of average shear stress to maximum shear stress for a circular section is
• A body is subjected to a direct tensile stress of 300 Mpa in one plane accompanied by a simple shear stress of 200 Mpa. The maximum normal stress will be
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• The deformation of any structure takes place in such a manner that the work of deformation is a minimum. This is known as