Force required to punch a 15 mm hole in a mild steel pipe 5 mm thick, when ultimate shear stress of the plate is 500 N/mm2, will be nearly

Related MCQs

• The force required to punch a 25 mm hole in a mild steel pipe 10 mm thich, when ultimate shear stress of the plate is 500 N/mm2 will be nearly
• It is desired to punch a hole of 20 mm diameter in a plate 20 mm think. If the shear stress of mild steel is 30 kg/mm2, the force necessary for punching would be approximately in the range
• For punching a hole of 25 mm diameter in a plate 20 mm thick, if the shear stress of plate material is 30 kg/mm2, the force required would be
• A sheet metal 2 mm thick having a shear strength of 40 kg/cm2 is to receive a punch hole of 35 mm diameter. The force required to make the punching will be
• With a punch for which the maximum crushing stress is 4 times the maximum shearing stress of the plate, the biggest hole that can be punched in the plate would be of diameter equal to
• While punching a hole in a metal sheet using a punch, stress is developed in the Punch.
• A mild steel flat 3 m long 150 mm wide and 15 mm thick carries an axial tensile load of 150 kN. If the value of u for mild steel is 0.3, it can be concluded that
• A spring steel ribbon 3.2 mm wide, 0.5 mm thick is wound on a 500 mm diameter cylinder. If E = 2 x 105 N/mm2, the maximum stress in the steel will be
• At a point in a steel member, the major principal stress is 2000 kg/cm2 and the minor principal stress is compressive. If the uni-axial tensile yield stress is 2500 kg/cm2, then the magnitude of the minor principal stress at which yielding will commence, according to the maximum shearing stress theory, is
• In a thick cylindrical shell subjected to an internal pressure (p), the tangential stress is always a tensile stress where as the radial stress is a compressive stress