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Q. |
If the critical field in a Gunn diode oscillator is 3.2 KV/cm and effective length is 20 microns, then the critical voltage is: |
A. | 3.2 v |
B. | 6.4 v |
C. | 2.4 v |
D. | 6.5 v |
Answer» B. 6.4 v | |
Explanation: critical voltage of a gunn diode oscillator is given by the expression lec where l is the effective length and ec is the critical field. substituting the given values in the above equation, critical voltage is 6.4 volts. |
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