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| Q. |
If the critical field in a Gunn diode oscillator is 3.2 KV/cm and effective length is 20 microns, then the critical voltage is: |
| A. | 3.2 v |
| B. | 6.4 v |
| C. | 2.4 v |
| D. | 6.5 v |
| Answer» B. 6.4 v | |
| Explanation: critical voltage of a gunn diode oscillator is given by the expression lec where l is the effective length and ec is the critical field. substituting the given values in the above equation, critical voltage is 6.4 volts. | |
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