Q.

If the critical field in a Gunn diode oscillator is 3.2 KV/cm and effective length is 20 microns, then the critical voltage is:

A. 3.2 v
B. 6.4 v
C. 2.4 v
D. 6.5 v
Answer» B. 6.4 v
Explanation: critical voltage of a gunn diode oscillator is given by the expression lec where l is the effective length and ec is the critical field. substituting the given values in the above equation, critical voltage is 6.4 volts.
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