A serial in/parallel out, 4-bit shift register initially contains all 1s. The data nibble 0111 is waiting to enter. After four clock pulses, the register contains                  

Related MCQs

• A bidirectional 4-bit shift register is storing the nibble 1101. Its input is HIGH. The nibble 1011 is waiting to be entered on the serial data-input line. After three clock pulses, the shift register is storing                  
• Assume that a 4-bit serial in/serial out shift register is initially clear. We wish to store the nibble 1100. What will be the 4-bit pattern after the second clock pulse? (Right-most bit first)
• An 8-bit serial in/serial out shift register is used with a clock frequency of 150 kHz. What is the time delay between the serial input and the Q3 output?
• An 8-bit serial in/serial out shift register is used with a clock frequency of 2 MHz to achieve a time delay (td) of                  
• The group of bits 11001 is serially shifted (right-most bit first) into a 5-bit parallel output shift register with an initial state 01110. After three clock pulses, the register contains                  
• How many clock pulses will be required to completely load serially a 5-bit shift register?
• A shift register that will accept a parallel input or a bidirectional serial load and internal shift features is called as?
• What is the difference between a shift-right register and a shift-left register?
• With a 200 kHz clock frequency, eight bits can be serially entered into a shift register in
• Refer to the given figures (a) and (b). A logic analyzer is used to check the circuit in figure (a) and displays the waveforms shown in figure (b). The actual analyzer display shows all four data outputs, Q0-Q3. The analyzer's cursor is placed at position X and all four of the data output lines show a LOW level output. What is wrong, if anything, with the circuit?