Q. |
If the distance from the focus is 2 mm and the distance from the directrix is 0.5 mm then what is the value of eccentricity? |
A. | 0.4 |
B. | 4 |
C. | 0.04 |
D. | 40 |
Answer» B. 4 | |
Explanation: eccentricity is defined as the ratio of the distance from the focus to the distance from the directrix and it is denoted by e. therefore, by definition, e = 2 ÷ 0.5 = 4. hence the conic section is called as hyperbola. |
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