[Solved] If the distance from the focus is 2 mm and the distance from the directrix is 0.5 mm then what is the value of eccentricity?

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Q.	If the distance from the focus is 2 mm and the distance from the directrix is 0.5 mm then what is the value of eccentricity?
A.	0.4
B.	4
C.	0.04
D.	40
Answer» B. 4
Explanation: eccentricity is defined as the ratio of the distance from the focus to the distance from the directrix and it is denoted by e. therefore, by definition, e = 2 ÷ 0.5 = 4. hence the conic section is called as hyperbola.

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