McqMate
These multiple-choice questions (MCQs) are designed to enhance your knowledge and understanding in the following areas: Civil Engineering .
| 1. |
percentage of Indian rails routes are electrified. |
| A. | 66% |
| B. | 25% |
| C. | 45% |
| D. | 76% |
| Answer» C. 45% | |
| Explanation: it is the fourth largest railway network in the world by size, comprising 119,630 kilometres (74,330 mi) of total track | |
| 2. |
is the predominant gauge used by Indian railways. |
| A. | broad gauge |
| B. | narrow gauge |
| C. | metre gauge |
| D. | standard gauge |
| Answer» A. broad gauge | |
| Explanation: indian gauge 1,676 mm (5 ft 6 in) (a broad gauge) is the predominant gauge used by ir. | |
| 3. |
Sleepers (ties) are mostly made up of |
| A. | wood |
| B. | prestressed concrete |
| C. | metal |
| D. | steak |
| Answer» B. prestressed concrete | |
| Explanation: prestressed concrete is a form of concrete used in construction which is “pre-stressed” by being placed under compression prior to supporting any loads beyond its own dead weight. this compression is produced by the tensioning of high-strength “tendons” located within or adjacent to the concrete volume and is done to improve the performance of the concrete in service. | |
| 4. |
forms the trackbed upon which railroad ties (sleepers) are laid. |
| A. | track ballast |
| B. | concrete ballast |
| C. | rail ballast |
| D. | wooden ballast |
| Answer» A. track ballast | |
| Explanation: it is packed between, below, and around the ties. it is used to bear the load from the railroad ties, to facilitate drainage of water, and also to keep down vegetation that might interfere with the track structure. this | |
| 5. |
The surface of the head of each of the two rails can be maintained by using a |
| A. | rail header |
| B. | rail trimmer |
| C. | rail grinder |
| D. | rail cutter |
| Answer» C. rail grinder | |
| Explanation: a rail grinder (or rail grinder) is a maintenance of way vehicle or train used to restore the profile and remove irregularities | |
| 6. |
The track and ballast form the |
| A. | temporary way |
| B. | true way |
| C. | rigid way |
| D. | permanent way |
| Answer» D. permanent way | |
| Explanation: the permanent way is the elements of railway lines: generally the pairs of rails typically laid on the sleepers (“ties” in american parlance) embedded in ballast, intended to carry the ordinary trains of a railway. it is described as permanent way because in the earlier days of railway construction, contractors often laid a temporary track to transport spoil and materials about the site; when this work was substantially completed, the temporary track was taken up and the permanent way installed. | |
| 7. |
The longest railway platforms is |
| A. | state street subway, chicago |
| B. | gorakhpur railway station, up |
| C. | kharagpur, west bengal |
| D. | kollam junction, kerala |
| Answer» B. gorakhpur railway station, up | |
| Explanation: • gorakhpur railway station, uttar pradesh, india:1,366.33 m (4,483 ft) (longest in the world). | |
| 8. |
The design of horizontal and vertical alignments, super elevation, gradient is worst affected by |
| A. | length of vehicle |
| B. | width of vehicle |
| C. | speed of vehicle |
| D. | height of vehicle |
| Answer» C. speed of vehicle | |
| Explanation: all the geometric design features are worst affected by velocity of the vehicle only. | |
| 9. |
The most raised portion of the pavement is called |
| A. | super elevation |
| B. | camber |
| C. | crown |
| D. | kerb |
| Answer» C. crown | |
| Explanation: the most elevated or the highest portion of a pavement is called as a crown, whereas camber is the portion that is raised for drainage purposes. | |
| 10. |
The extra width of pavement is provided on |
| A. | horizontal curve |
| B. | width of pavement |
| C. | length of pavement |
| D. | super elevation |
| Answer» A. horizontal curve | |
| Explanation: extra width of the pavement is provided on horizontal curve to avoid the skidding, if the vehicle negotiates the curve then the centrifugal force will act towards outside and there is a chance of skidding, to avoid this extra width is provided. | |
| 11. |
Transition curve is introduced in |
| A. | horizontal curve |
| B. | circular curve |
| C. | between horizontal curve and circular curve |
| D. | vertical curve |
| Answer» C. between horizontal curve and circular curve | |
| Explanation: a transition curve is introduced between horizontal curve and circular curve, the transition curve slowly introduces the centrifugal acceleration to avoid the danger of skidding. | |
| 12. |
The most important factor that is required for road geometrics is |
| A. | ssd |
| B. | osd |
| C. | isd |
| D. | speed of vehicle |
| Answer» D. speed of vehicle | |
| Explanation: the road user characteristics, traffic and vehicular characteristics mostly influence the road geometric design but the most important factor is the speed of vehicle. | |
| 13. |
The design speed of NH on a cross slope of up to 10% is |
| A. | 100kmph |
| B. | 80kmph |
| C. | 60kmph |
| D. | 50kmph |
| Answer» A. 100kmph | |
| Explanation: the ruling speed up to a cross slope of 10% is 100kmph; it decreases with an increase in increase of cross slope. | |
| 14. |
A part of pavement raised with respect to one side keeping the other side constant is called |
| A. | footpath |
| B. | kerb |
| C. | super elevation |
| D. | camber |
| Answer» C. super elevation | |
| Explanation: the super elevation is a portion of pavement raised on outer edge with respect to inner edge or both edges raised with respect to centre. | |
| 15. |
The main purpose of providing camber is |
| A. | to collect storm water |
| B. | to maintain equilibrium |
| C. | to follow irc specifications |
| D. | to follow geometric specifications |
| Answer» A. to collect storm water | |
| Explanation: during the rainy season the roads are usually flooded with water so to keep the pavement dry they have to be drained off so the road is provided with a camber. | |
| 16. |
The legal axle load of the design vehicle used in India is? |
| A. | 1.6 tonne |
| B. | 8.2 tonne |
| C. | 16.2 tonne |
| D. | 32.4 tonne |
| Answer» B. 8.2 tonne | |
| Explanation: the legal axle load used for the design of pavements is 8.2 tonnes; usually they are expressed in msa (million standard axles). | |
| 17. |
In India, the type of traffic assumed to design pavements is? |
| A. | low traffic |
| B. | heavy traffic |
| C. | mixed traffic flow |
| D. | very low traffic |
| Answer» C. mixed traffic flow | |
| Explanation: in india generally there is always a mixed traffic flow except during midnight hours and early morning hours, so the designer has to assume mixed traffic flow only. | |
| 18. |
The final choice of stabilisation technique is based on |
| A. | labour |
| B. | material |
| C. | equipment |
| D. | cost |
| Answer» D. cost | |
| Explanation: though all the equipment, labour and materials are equally important, the final factor is cost. | |
| 19. |
The flexural strength is based on |
| A. | irc |
| B. | plate test |
| C. | cbr |
| D. | shear |
| Answer» C. cbr | |
| Explanation: the most commonly used method for testing the strength of the flexible pavement. | |
| 20. |
How many types of challenges are encountered in bitumen stabilisation? |
| A. | one |
| B. | two |
| C. | three |
| D. | four |
| Answer» C. three | |
| Explanation: the major problems are choice of stabilisation, design mix and thickness of layer. | |
| 21. |
The mix design should take into consideration is? |
| A. | stability |
| B. | durability |
| C. | stability and durability |
| D. | age |
| Answer» C. stability and durability | |
| Explanation: the mix should take into consideration, the stability and durability requirements, strength is also equally important. | |
| 22. |
The modification factor used in base course thickness is called |
| A. | granite equivalence |
| B. | gravel equivalence |
| C. | sand equivalence |
| D. | soil equivalence |
| Answer» B. gravel equivalence | |
| Explanation: in the thickness of the pavement layer the mix can’t be designed | |
| 23. |
The colloidal content in BC soils can be up to |
| A. | 20% |
| B. | 30% |
| C. | 40% |
| D. | 50% |
| Answer» D. 50% | |
| Explanation: the colloidal content in the soil may be up 50%, which is an undesirable property for pavement. | |
| 24. |
What is the shrinkage limit value in BC soil? |
| A. | 0% |
| B. | 9% |
| C. | 15% |
| D. | 16% |
| Answer» C. 15% | |
| Explanation: the bc soils have a less shrinkage limit value from 10% to 15 %, which is a very high value, whereas in sand and silt they don’t exist. | |
| 25. |
The cement content required for BC soil is |
| A. | high |
| B. | very high |
| C. | low |
| D. | very low |
| Answer» B. very high | |
| Explanation: the cement content required for the cement is 15 to 25%, so it is not advisable to directly stabilize with cement. | |
| 26. |
The desert sand is |
| A. | strong |
| B. | weak |
| C. | normal |
| D. | unfit for pavements |
| Answer» B. weak | |
| Explanation: the sand in the desert is very | |
| 27. |
The water content in the emulsion is about |
| A. | 10% |
| B. | 20% |
| C. | 30% |
| D. | 40% |
| Answer» D. 40% | |
| Explanation: the emulsion in the mix consists of 40% of water, hence it is used for stabilisation of desert sand. | |
| 28. |
The distance shown by red line represents |
| A. | separation |
| B. | parallel way |
| C. | height |
| D. | gauge |
| Answer» D. gauge | |
| Explanation: during the early days of rail, there was considerable variation in the gauge used by different systems. today, 54.8% of the world’s railways use a gauge of 1,435 mm | |
| 29. |
Name the organization which is the research and development wing of Indian Railways. |
| A. | cris |
| B. | rdso |
| C. | rsdo |
| D. | irctc |
| Answer» B. rdso | |
| Explanation: the rdso (research, designs and standards organization) acts as the technical advisor and consultant to the ministry of railways and their production units. | |
| 30. |
The Railways has a degree of freedom for its movement. |
| A. | single |
| B. | two |
| C. | three |
| D. | four |
| Answer» A. single | |
| Explanation: degree of freedom refers to the number of directions in which a vehicle can move. since trains have to run on the provided tracks, their movement is restricted to one direction only, compared to road transport which can move in x, y and z directions. | |
| 31. |
Track modulus is defined as: |
| A. | load/unit length of sleeper |
| B. | load/unit length of sleeper to produce depression in rail |
| C. | load/unit length of rail to produce depression in sleeper |
| D. | load/unit length of rail to produce unit depression/deflection in track |
| Answer» D. load/unit length of rail to produce unit depression/deflection in track | |
| Explanation: the track modulus defines the stiffness of track or its load bearing capacity. it is based on the elastic theory. when a load causes a deflection on the top of the rail, the deformation comes on the sleeper, below the rail. | |
| 32. |
The track modulus is not affected by gauges. |
| A. | true |
| B. | false |
| Answer» B. false | |
| Explanation: as the three gauges (narrow- ng, metre –mg and broad-bg) increases, the components of the permanent part (like ballast and sleeper) also increases in size. as a result track modulus also increases. the recommended track modulus is: bg = 70 to 90kg/cm2, mg=42-54kg/cm2 and ng=30kg/cm2. | |
| 33. |
Which of the following causes stresses in Sleepers? |
| A. | eccentric vertical loads |
| B. | contact shear stress of wheel and rail |
| C. | lateral deflection of sleepers |
| D. | track components |
| Answer» D. track components | |
| Explanation: the track components like the track modulus, the stiffness of rail, design of the sleeper, sleeper density (number of sleepers provided) and their load bearing capacity are factors which cause stresses in sleepers. the other 3 options are responsible for stresses in rails. | |
| 34. |
There are types of rail sections. |
| A. | 2 |
| B. | 3 |
| C. | 4 |
| D. | 5 |
| Answer» B. 3 | |
| Explanation: the three types of rail sections | |
| 35. |
How does the depth of ballast cushion affect rail section? |
| A. | higher the depth bigger the rail section |
| B. | depth is less, bigger the rail section |
| C. | depth is less, smaller the rail section |
| D. | depth and rail section same |
| Answer» B. depth is less, bigger the rail section | |
| Explanation: the selection of the rail section depends on many factors like heaviest axle loads, maximum permissible speed, type of sleepers and depth of ballast cushion. if the depth of the ballast cushion is less, then a bigger rail section has to be provided. | |
| 36. |
The mountain alignment can be classified into types. |
| A. | 4 |
| B. | 3 |
| C. | 2 |
| D. | 1 |
| Answer» C. 2 | |
| Explanation: they are the zig-zag development and the switch back development. in the zig-zag developments, the alignments try to follow the contours of the region to an extent. in the switch back, certain contours like steep slopes have to be negotiated and may use buffer stops. | |
| 37. |
What must be done to wooden sleepers before use? |
| A. | seasoning |
| B. | washing |
| C. | painting |
| D. | hydrating |
| Answer» A. seasoning | |
| Explanation: the wood for the sleepers is taken directly from the trees and they contain moisture. in order to reduce the moisture content, seasoning is adopted. in india, air | |
| 38. |
Airports can be classified on how many basis? |
| A. | 5 |
| B. | 4 |
| C. | 3 |
| D. | 2 |
| Answer» B. 4 | |
| Explanation: the airports can be classified into 4 on the basis of take-off and landing, geometric design, based on aircraft approach speed (faa) and function. | |
| 39. |
ICAO classification system considers how many things? |
| A. | 2 |
| B. | 4 |
| C. | 5 |
| D. | 6 |
| Answer» A. 2 | |
| Explanation: the icao classification system is based on geometric designs broadly. it mainly considers 2 things for its classification | |
| 40. |
The FAA classification of the airport is based on: |
| A. | function |
| B. | geometric design |
| C. | airport approach speed |
| D. | length of runway |
| Answer» C. airport approach speed | |
| Explanation: the faa or federal aviation administration classifies on the basis of the aircraft approach speed, given in knots. they are ranging from category a<91 knots to category e>186 knots. | |
| 41. |
Which of the following is not a characteristic of centralized system of the terminal Area? |
| A. | passengers, cargo routed centrally |
| B. | passenger facilities in small units |
| C. | walking distance to aircraft < 200m |
| D. | common facilities for different gate positions |
| Answer» B. passenger facilities in small units | |
| Explanation: the passenger facilities are arranged in smaller units or provided separately at different locations in a decentralised system. each unit will have aircraft gate positions. | |
| 42. |
Which of the below does not affect the site- selection of an airport site? |
| A. | adequate access |
| B. | air traffic potential |
| C. | sufficient airspace |
| D. | number of ground staff |
| Answer» D. number of ground staff | |
| Explanation: the other 3 options are the specific aspects on which the site-selection is dependent. the site should be accessible by people easily from different locations, there should be potential for air traffic – flight or passenger and sufficient airspace for airports | |
| 43. |
Runways are oriented in a direction against the prevailing wind. |
| A. | true |
| B. | false |
| Answer» B. false | |
| Explanation: the runways are oriented in the direction of the wind so that it can utilize the force provided by the wind for take-off and landing of the aircraft. | |
| 44. |
The wind intensity during a calm period in runways should be: |
| A. | below 4.6km/hr |
| B. | above 5km/hr |
| C. | between 5-10 km/hr |
| D. | below 6.4km/hr |
| Answer» D. below 6.4km/hr | |
| Explanation: the wind intensity should remain below 6.4km/hr during a calm period and it is the same for all wind direction. it is equal to 100 minus the total wind coverage. | |
| 45. |
The application of diagram is used to find the orientation of the runway to get the desired wind coverage. |
| A. | wind butterfly |
| B. | wind cycle |
| C. | wind star |
| D. | wind rose |
| Answer» D. wind rose | |
| Explanation: an average date of around 5-10 years of the various components of wind (intensity, duration and direction) of the area is compiled to make a wind rose diagram. | |
| 46. |
Elevation of airport site above MSL is a factor that controls airport size. |
| A. | true |
| B. | false |
| Answer» A. true | |
| Explanation: it is one of the factors. as the elevation increases, the meteorological conditions like air pressure and density reduces. as a result, bigger size of facilities has to be provided. | |
| 47. |
How many types of Fly Rules are there? |
| A. | 2 |
| B. | 5 |
| C. | 4 |
| D. | 3 |
| Answer» A. 2 | |
| Explanation: there are 2 fly rules; the vfr (visual flight rules) and ifr (instrumental fly rules). the vfr allows the aircraft to be operated within reasonable conditions by oneself. in ifr, the operations are entirely controlled by instruments. a flight plan is required in both cases. | |
| 48. |
Term marked by ’?’ in diagram is |
| A. | tip chord |
| B. | root chord |
| C. | thrust |
| D. | lift |
| Answer» A. tip chord | |
| Explanation: typical wing planform is shown in figure. chord at the fuselage section is called root chord. chord at wing tip is called tip chord. thrust is a propulsive force. lift is an upward force. | |
| 49. |
Let’s consider flat wrapping is to be used for lofting. If wing has taper ratio of 0.4, span of 26.6ft and root chord Cr is 76in then, find the area to be covered by flat wrapping. |
| A. | 118ft2 |
| B. | 200ft2 |
| C. | 1600in |
| D. | 10m |
| Answer» A. 118ft2 | |
| Explanation: given, cr = 76in = 76*12ft = 912ft, span b=26.6ft, taper ratio t=0.4 | |
| 50. |
From following diagram find the value of MAC of wing. |
| A. | 5.8m |
| B. | 6.8m |
| C. | 2.5m |
| D. | 10m |
| Answer» A. 5.8m | |
| Explanation: given, cr = 10m, ct = 2m and taper ratio t = ct/cr = 2/10 = 0.2 | |
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