Q.

An object of mass 0.2kg executes simple harmonic motion along the x-axis with a frequency of (25/π)Hz. At the position x = 0.04, the object has kinetic energy of 0.5J and potential energy 0.4J. The amplitude of oscillation is?

A. 6cm
B. 4cm
C. 8cm
D. 2cm
Answer» A. 6cm
Explanation: total energy, e=2π2 mv2 a2 0.5+0.4=2π2×0.2×(25/π)2 a2 a2=0.9/(0.4×252) a=3/(2×25)=3/50 m=6cm.
876
0
Do you find this helpful?
1

View all MCQs in

Engineering Physics

Discussion

No comments yet