

McqMate
These multiple-choice questions (MCQs) are designed to enhance your knowledge and understanding in the following areas: Electrical Engineering .
151. |
The non coherent FSK needs Eb/N0 than coherent FSK. |
A. | 1db more |
B. | 1db less |
C. | 3db more |
D. | 3db less |
Answer» A. 1db more |
152. |
The DPSK needs Eb/N0 than BPSK. |
A. | 1db more |
B. | 1db less |
C. | 3db more |
D. | 3db less |
Answer» A. 1db more |
153. |
Which is easier to implement and is preferred? |
A. | coherent system |
B. | non coherent system |
C. | coherent & non coherent system |
D. | none of the mentioned |
Answer» B. non coherent system |
154. |
Which is the main system consideration? |
A. | probability of error |
B. | system complexity |
C. | random fading channel |
D. | all of the mentioned |
Answer» D. all of the mentioned |
155. |
In the frequency of the carrier signal is varied based on the information in an a digital signal |
A. | ask |
B. | psk |
C. | fsk |
D. | qam |
Answer» C. fsk |
156. |
In the amplitude of the carrier signal is varied based on the information in an a digital signal |
A. | ask |
B. | psk |
C. | fsk |
D. | qam |
Answer» A. ask |
157. |
In modulation , the bit rate is 8 times the baud rate |
A. | 8-qam |
B. | 64-qam |
C. | 256-qam |
D. | none of above |
Answer» C. 256-qam |
158. |
In modulation , the baud rate is 1/4 times the bit rate |
A. | 4-qam |
B. | 2-psk |
C. | 4-psk |
D. | none of above |
Answer» D. none of above |
159. |
Which of the following is not a characteristic of PN sequence? |
A. | balance property |
B. | autocorrelation property |
C. | run property |
D. | non deterministic |
Answer» D. non deterministic |
160. |
symbols. |
A. | 2m |
B. | m |
C. | 2m |
D. | 2m-1 |
Answer» D. 2m-1 |
161. |
PN sequence can be generated using . |
A. | sequential logic circuits |
B. | op-amp |
C. | timer ic |
D. | mosfet |
Answer» A. sequential logic circuits |
162. |
DSSS system spreads the baseband signal by the baseband pulses with a pseudo noise sequence. |
A. | adding |
B. | subtracting |
C. | multiplying |
D. | dividing |
Answer» C. multiplying |
163. |
Frequency hopping involves a periodic change of transmission |
A. | signal |
B. | frequency |
C. | phase |
D. | amplitude |
Answer» B. frequency |
164. |
What is the set of possible carrier frequencies in FH-SS? |
A. | hopset |
B. | hop |
C. | chips |
D. | symbols |
Answer» A. hopset |
165. |
The bandwidth of the channel used in the hopset is called |
A. | hopping bandwidth |
B. | total hopping bandwidth |
C. | instantaneous bandwidth |
D. | 3 db bandwidth |
Answer» C. instantaneous bandwidth |
166. |
The processing gain of FH systems is given by ratio of |
A. | hopping bandwidth and hopping period |
B. | instantaneous bandwidth and hopping duration |
C. | 3 db bandwidth and bit rate |
D. | total hopping bandwidth and instantaneous bandwidth |
Answer» D. total hopping bandwidth and instantaneous bandwidth |
167. |
Pseudorandom signal predicted. |
A. | can be |
B. | cannot be |
C. | maybe |
D. | none of the mentioned |
Answer» A. can be |
168. |
In FH-SS which of the following Modulation Demodulation Technique has been used |
A. | bpsk |
B. | fsk |
C. | ask |
D. | qam |
Answer» B. fsk |
169. |
In DS-SS which of the following Modulation Demodulation Technique has been used |
A. | bpsk |
B. | fsk |
C. | ask |
D. | qam |
Answer» A. bpsk |
170. |
Frequency division multiple access (FDMA) assigns channels to users. |
A. | individual, individual |
B. | many, individual |
C. | individual, many |
D. | many, many |
Answer» A. individual, individual |
171. |
The FDMA channel carries phone circuit at a time. |
A. | ten |
B. | two |
C. | one |
D. | several |
Answer» C. one |
172. |
The bandwidth of FDMA channel is |
A. | wide |
B. | narrow |
C. | large |
D. | zero |
Answer» B. narrow |
173. |
The symbol time in FDMA systems is thus intersymbol interference is |
A. | large, high |
B. | small, low |
C. | small, high |
D. | large, low |
Answer» D. large, low |
174. |
Due to transmission scheme bits are needed for overhead in FDMA systems. |
A. | continuous, few |
B. | discontinuous, few |
C. | continuous, many |
D. | discontinuous, many |
Answer» A. continuous, few |
175. |
is based on FDMA/FDD. |
A. | gsm |
B. | w-cdma |
C. | cordless telephone |
D. | amps |
Answer» D. amps |
176. |
Which of the following is not true for TDMA? |
A. | single carrier frequency for single user |
B. | discontinuous data transmission |
C. | no requirement of duplexers |
D. | high transmission rates |
Answer» A. single carrier frequency for single user |
177. |
Because of transmissions in TDMA, the handoff process in |
A. | continuous, complex |
B. | continuous, simple |
C. | discontinuous, complex |
D. | discontinuous, simple |
Answer» D. discontinuous, simple |
178. |
synchronization overhead is required in TDMA due to transmission. |
A. | high, burst |
B. | high, continuous |
C. | low, burst |
D. | no, burst |
Answer» A. high, burst |
179. |
of TDMA system is a measure of the percentage of transmitted data that contains information as opposed to providing overhead for the access scheme. |
A. | efficiency |
B. | figure of merit |
C. | signal to noise ratio |
D. | mean |
Answer» A. efficiency |
180. |
A TDMA system uses 25 MHz for the forward link, which is broken into radio channels of 200 kHz. If 8 speech channels are supported on a single radio channel, how many simultaneous users can be accommodated? |
A. | 25 |
B. | 200 |
C. | 1600 |
D. | 1000 |
Answer» D. 1000 |
181. |
US digital cellular system based on CDMA was standardized as |
A. | is-54 |
B. | is-136 |
C. | is-95 |
D. | is-76 |
Answer» C. is-95 |
182. |
Which of the following technique used in CDMA |
A. | qam |
B. | gmsk |
C. | ds-ss bpsk |
D. | fh-ss fsk |
Answer» C. ds-ss bpsk |
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