McqMate
1. 
The phenomena of development of internal tensile stresses in a concrete member by means of tensioning devices are called as 
A.  pretensioning 
B.  posttensioning 
C.  prestressing of concrete 
D.  thermoelectric prestressing 
Answer» C. prestressing of concrete 
2. 
In reinforced concrete members the prestress is commonly introduced by 
A.  tensioning the steel reinforcement 
B.  tendons 
C.  shortening of concrete 
D.  rings 
Answer» A. tensioning the steel reinforcement 
3. 
Which of the following basic concept is involved in the analysis of prestressed concrete members? 
A.  combined and bending stresses 
B.  principle stresses 
C.  shear stresses 
D.  overhead stresses 
Answer» A. combined and bending stresses 
4. 
The prestressing of concrete member is carried out to reduce 
A.  compressive stresses 
B.  tensile stresses 
C.  bending stresses 
D.  shear force 
Answer» A. compressive stresses 
5. 
The earliest examples of wooden barrel construction by forcefitting of metal bands and shrinkfitting of metal tiers of wooden wheels indicate the art of 
A.  prestressing 
B.  tensioning 
C.  stress 
D.  straining 
Answer» A. prestressing 
6. 
The concept is used in many branches of civil engineering and building construction? 
A.  reinforced concrete 
B.  prestressed concrete 
C.  steel concrete 
D.  lump sum concrete 
Answer» B. prestressed concrete 
7. 
The attempt to introduce permanently acting forces in concrete to resist the elastic forces is 
A.  prestressing 
B.  loading 
C.  prestraining 
D.  bending 
Answer» A. prestressing 
8. 
In reinforced concrete members, the prestress commonly introduced is 
A.  tensioning steel reinforcement 
B.  tensioning wood reinforcement 
C.  tensioning rings 
D.  tensioning plates 
Answer» A. tensioning steel reinforcement 
9. 
Development of early cracks in reinforced concrete is due to 
A.  strains of steel 
B.  stresses of steel 
C.  ultimate load 
D.  bending of steel 
Answer» A. strains of steel 
10. 
The significant observations which resulted from the pioneering research on prestressed concrete were 
A.  high strength steel and losses of prestress 
B.  high strength tendon and losses of creep 
C.  high strength bars and losses of strain 
D.  high strength rings and losses of shrinkage 
Answer» A. high strength steel and losses of prestress 
11. 
The necessity of high strength concrete in prestressed concrete is due to 
A.  shear and bonding 
B.  loading and unloading 
C.  cracking 
D.  bending 
Answer» A. shear and bonding 
12. 
In the zone of anchorages the material preferred to minimize costs is 
A.  high strength steel 
B.  high strength bars 
C.  high strength tendons 
D.  high strength concrete 
Answer» D. high strength concrete 
13. 
The length of the prestressing tendon between the end of the member and the point where the steel attains its stress is called 
A.  anchorage 
B.  de bonding 
C.  cracking load 
D.  transmission length 
Answer» D. transmission length 
14. 
In cab cable, the curved portion of the tendon and anchors lie in 
A.  compression and tension zone 
B.  cracking zone 
C.  tension and compression zone 
D.  loading zone 
Answer» C. tension and compression zone 
15. 
The load at which the prestressed member develops its first crack is called as 
A.  transfer load 
B.  creep load 
C.  bending load 
D.  cracking load 
Answer» D. cracking load 
16. 
In circular prestressing members, the tendons are supplied in form of 
A.  cables 
B.  bars 
C.  wires 
D.  rings 
Answer» D. rings 
17. 
In case of continuous prestressed concrete members to gain continuity, splicing is done by 
A.  reinforcement 
B.  steel 
C.  concrete 
D.  tendons 
Answer» D. tendons 
18. 
The phenomena of drying process of contraction concrete refer to 
A.  moisture loss 
B.  shrinkage of concrete 
C.  drying process 
D.  weight loss 
Answer» B. shrinkage of concrete 
19. 
The ratio between the creep strain and elastic strain of concrete is defined as 
A.  creep ratio 
B.  creep elasticity 
C.  creep coefficient 
D.  creep factor 
Answer» C. creep coefficient 
20. 
The phenomena of reduction of stress in steel at a constant strain are known as 
A.  reduction of stress 
B.  relaxation of stress 
C.  de bonding 
D.  proof stress 
Answer» C. de bonding 
21. 
A device which helps the tendons to transmit prestress to the member and maintain it for the design period is? 
A.  cab cable 
B.  anchorage 
C.  tendon 
D.  transfer 
Answer» C. tendon 
22. 
Which of the following type of prestress applied to concrete in which tensile stresses to a limited degree are permitted is known as 
A.  moderate prestressing 
B.  partial prestressing 
C.  full prestressing 
D.  axial prestressing 
Answer» B. partial prestressing 
23. 
Prevention of bond between the steel and concrete is known as 
A.  bond prestressed concrete 
B.  axial prestressing 
C.  de bonding 
D.  proof stress 
Answer» C. de bonding 
24. 
Which one of the following is the basic assumption involved in designing of prestressed concrete members? 
A.  plane member remains plane before and after bending 
B.  variation of stresses in tensile reinforcement 
C.  development of principle stresses 
D.  hooke’s law is not valid for prestressing 
Answer» A. plane member remains plane before and after bending 
25. 
The compression in concrete and tension in steel are developed by? 
A.  joint cements 
B.  expansion cements 
C.  water cement ratio 
D.  hardened cements 
Answer» B. expansion cements 
26. 
In pretensioning system, after curing and hardening of concrete the reinforcement is set 
A.  free 
B.  fixed 
C.  locked 
D.  jacked 
Answer» B. fixed 
27. 
The method of prestressing the concrete after it attains its strength is known as 
A.  pre tensioning 
B.  post tensioning 
C.  chemical prestressing 
D.  axial prestressing 
Answer» B. post tensioning 
28. 
The ultimate strength of high tensile steel is 
A.  1100 
B.  2100 
C.  1500 
D.  1250 
Answer» B. 2100 
29. 
The high tensile steel is obtained by increasing content of 
A.  carbon content in steel 
B.  aluminium content in steel 
C.  manganese content in steel 
D.  sulphur content in steel 
Answer» A. carbon content in steel 
30. 
The permissible stress in prestressing steel should not exceed 
A.  80% 
B.  60% 
C.  50% 
D.  70% 
Answer» A. 80% 
31. 
When the concrete attains sufficient strength, which elements are released? 
A.  jacks 
B.  casting bed 
C.  tendons 
D.  beams 
Answer» A. jacks 
32. 
Which is one of the systems used for pretensioning? 
A.  magnelbalton system 
B.  freyssinet system 
C.  giffordudall system 
D.  hoyer’s long line method 
Answer» D. hoyer’s long line method 
33. 
Hoyer’s system of pre tensioning is generally adopted for 
A.  small scale members 
B.  large scale members 
C.  middle span members 
D.  end members 
Answer» B. large scale members 
34. 
The transfer of prestress of concrete is achieved by 
A.  plates 
B.  rings 
C.  steel bars 
D.  jacks 
Answer» D. jacks 
35. 
The bond of prestressing wires in Hoyer’s system can be formed by 
A.  helical crimping 
B.  tangential crimping 
C.  circular crimping 
D.  diode crimping 
Answer» A. helical crimping 
36. 
The Hoyer’s method of prestressing is done by 
A.  pulling out of wires 
B.  pushing wires 
C.  heating of wires 
D.  stressing of wires 
Answer» A. pulling out of wires 
37. 
Hoyer’s system of pretensioning can be done for beams. 
A.  2 
B.  more than 2 
C.  less than 2 
D.  3 
Answer» B. more than 2 
38. 
In post tensioning, the concrete units are cast by 
A.  ducts 
B.  jacks 
C.  anchorages 
D.  wedges 
Answer» A. ducts 
39. 
After the tensioning operation, the space between the tendons and the ducts are 
A.  layered 
B.  grouted 
C.  cemented 
D.  drilled 
Answer» B. grouted 
40. 
A slab without beam is called as 
A.  bubble deck slab 
B.  grid slab 
C.  flat slab 
D.  both (a) and (c) 
Answer» C. flat slab 
41. 
According to IS 456: 2000, a flat slab can be design by direct design method if there are continuous span in each direction 
A.  minimum 3 
B.  maximum 3 
C.  minimum 4 
D.  no limitation on spans 
Answer» A. minimum 3 
42. 
A flat slab can be design by 
A.  direct design method 
B.  equivalent frame method 
C.  both (a) and (b) 
D.  eulers method 
Answer» C. both (a) and (b) 
43. 
The panels shall be rectangular, and the ratio of the longer span to the shorter span within a panel shall 
A.  not be less than 3.0 
B.  not be greater than 2.0 
C.  not be greater than 3.0 
D.  not be less than 2.0 
Answer» B. not be greater than 2.0 
44. 
In flat slab design, in an interior span total design moment Mo shall be distributed in proportion 
A.  25 % negative design moment & 75 % positive design moment 
B.  75 % negative design moment & 255 % positive design moment 
C.  35 % negative design moment & 65 % positive design moment 
D.  65 % negative design moment & 35 % positive design moment 
Answer» D. 65 % negative design moment & 35 % positive design moment 
45. 
In direct design method of flat slab design, At an interior support, the column strip shall be designed to resist 
A.  75 percent of the total positive moment in the panel at that support 
B.  25 percent of the total negative moment in the panel at that support 
C.  75 percent of the total negative moment in the panel at that support 
D.  65 percent of the total negative moment in the panel at that support 
Answer» C. 75 percent of the total negative moment in the panel at that support 
46. 
In direct design method of flat slab design, At an exterior support, the column strip shall be designed to resist the 
A.  total negative moment in the panel at that support. 
B.  total positive moment in the panel at that support. 
C.  75 % of total negative moment in the panel at that support. 
D.  75 % of total positive moment in the panel at that support. 
Answer» A. total negative moment in the panel at that support. 
47. 
In flat slab design, The drops when provided shall be rectangular in plan, and have a length in each direction 
A.  not less than three fourth of the panel length in that direction 
B.  not less than one fourth of the panel length in that direction 
C.  not less than one half of the panel length in that direction 
D.  not less than one third of the panel length in that direction 
Answer» D. not less than one third of the panel length in that direction 
48. 
In flat slab design, the column strip shall be designed to resist 
A.  60 percent of the total positive moment in the panel 
B.  40 percent of the total positive moment in the panel 
C.  35 percent of the total negative moment in the panel 
D.  65 percent of the total negative moment in the panel 
Answer» A. 60 percent of the total positive moment in the panel 
49. 
In flat slab design, the middle strip shall be designed to resist 
A.  60 percent of the total positive moment in the panel 
B.  40 percent of the total positive moment in the panel 
C.  35 percent of the total negative moment in the panel 
D.  65 percent of the total negative moment in the panel 
Answer» B. 40 percent of the total positive moment in the panel 
50. 
In design of flat slab, The critical section for shear shall be at a distance 
A.  effective depth /2 from the periphery of the column/capital/drop panel 
B.  effective depth from the periphery of the column/capital/drop panel 
C.  face of the column/capital/drop panel 
D.  none of the above 
Answer» A. effective depth /2 from the periphery of the column/capital/drop panel 
51. 
In flat slab design, When drop panels are used, the thickness of drop panel for determination of area of reinforcement shall be 
A.  equal to thickness of drop 
B.  equal to thickness of slab plus one quarter the distance between edge of drop and edge of capital 
C.  lesser of (a) and (b) 
D.  greater of (a) and (b) 
Answer» C. lesser of (a) and (b) 
52. 
In flat slab design, let τv = shear stress at critical section and τc = permissible shear stress in concrete , then no shear reinforcement is required 
A.  if τv < τc 
B.  if τc < τv < 1.5 τc 
C.  if τv > τc 
D.  if τv > 1.5τc 
Answer» A. if τv < τc 
53. 
In flat slab design, let τv = shear stress at critical section and τc = permissible shear stress in concrete , then shear reinforcement shall be provided 
A.  if τv < τc 
B.  if τc < τv < 1.5 τc 
C.  if τv > τc 
D.  if τv > 1.5τc 
Answer» B. if τc < τv < 1.5 τc 
54. 
In flat slab design, let τv = shear stress at critical section and τc = permissible shear stress in concrete , then flat slab is redesigned 
A.  if τv < τc 
B.  if τc < τv < 1.5 τc 
C.  if τv > τc 
D.  if τv > 1.5τc 
Answer» D. if τv > 1.5τc 
55. 
In flat slab design, the moment at the support of column strip is 
A.  0 
B.  positive 
C.  negative 
D.  may be positive or negative 
Answer» C. negative 
56. 
In limit state method of design of flat slab, τc = permissible shear stress in concrete 
A.  τc = 0.25 √fck 
B.  τc = 0.16 √fck 
C.  τc = 0.45 √fck 
D.  τc = 0.70 √fck 
Answer» A. τc = 0.25 √fck 
57. 
In working method of design of flat slab, τc = permissible shear stress in concrete 
A.  τc = 0.25 √fck 
B.  τc = 0.16 √fck 
C.  τc = 0.45 √fck 
D.  τc = 0.70 √fck 
Answer» B. τc = 0.16 √fck 
58. 
In direct design method of flat slab, total design moment Mo is 945 kNm then negative design moment in middle strip is 
A.  368.55 knm 
B.  245.70 knm 
C.  198.45 knm 
D.  132.30 knm 
Answer» B. 245.70 knm 
59. 
In direct design method of flat slab, total design moment Mo is 945 kNm then negative design moment in column strip is 
A.  368.55 knm 
B.  245.70 knm 
C.  198.45 knm 
D.  132.30 knm 
Answer» A. 368.55 knm 
60. 
In direct design method of flat slab, total design moment Mo is 945 kNm then positive design moment in middle strip is 
A.  330.75 knm 
B.  614.25 knm 
C.  198.45 knm 
D.  132.30 knm 
Answer» D. 132.30 knm 
61. 
In direct design method of flat slab, total design moment Mo is 945 kNm then positive design moment in column strip is 
A.  330.75 knm 
B.  614.25 knm 
C.  198.45 knm 
D.  132.30 knm 
Answer» C. 198.45 knm 
62. 
In direct design method of flat slab, total design moment Mo is 945 kNm then positive design moment is 
A.  330.75 knm 
B.  614.25 knm 
C.  236.25 knm 
D.  708.75 knm 
Answer» A. 330.75 knm 
63. 
In direct design method of flat slab, total design moment Mo is 945 kNm then negative design moment is 
A.  330.75 knm 
B.  614.25 knm 
C.  236.25 knm 
D.  708.75 knm 
Answer» B. 614.25 knm 
64. 
The pressure exerted by the retained material on the retaining wall is called 
A.  active earth pressure 
B.  earth pressure 
C.  passive earth pressure 
D.  both (a) and (b) 
Answer» D. both (a) and (b) 
65. 
A retaining wall which resist the earth pressure due to backfill by its dead weight is called 
A.  cantilever retaining wall 
B.  gravity wall 
C.  counterfort retaining wall 
D.  buttress retaining wall 
Answer» A. cantilever retaining wall 
66. 
Cantilever RC retaining wall proves to be economical for height 
A.  5m to 7m 
B.  8m to 10m 
C.  11 m to 15m 
D.  more than 15m 
Answer» A. 5m to 7m 
67. 
Let H= height of retaining wall, ϒ=unit weight of backfill and ka = coefficient of active earth pressure, kp = coefficient of passive earth pressure, then the intensity of active earth pressure per unit area of wall at any depth ‘h’ below top of the wall is given by 
A.  pa = ka ϒ h 
B.  pa = kp ϒ h 
C.  pa = ka ϒ h2 /2 
D.  pa = ka ϒ h3 /6 
Answer» A. pa = ka ϒ h 
68. 
Let H= height of retaining wall, ϒ=unit weight of backfill and ka = coefficient of active earth pressure, kp = coefficient of passive earth pressure, then total pressure at any height ‘h’ below top of the wall is given by 
A.  pa = ka ϒ h 
B.  pa = kp ϒ h 
C.  pa = ka ϒ h2 /2 
D.  pa = ka ϒ h3 /6 
Answer» C. pa = ka ϒ h2 /2 
69. 
Let H= height of retaining wall, ϒ=unit weight of backfill and ka = coefficient of active earth pressure, kp = coefficient of passive earth pressure, then bending moment at any height ‘h’ below top of the wall is given by 
A.  pa = ka ϒ h 
B.  pa = kp ϒ h 
C.  pa = ka ϒ h2 /2 
D.  pa = ka ϒ h3 /6 
Answer» D. pa = ka ϒ h3 /6 
70. 
Coefficient of active earth pressure ka 
A.  ka = 1sinϕ / 1+sinϕ 
B.  ka = 1sin2ϕ / 1+sin2ϕ 
C.  ka = 1+sinϕ / 1sinϕ 
D.  ka = 1+sin2ϕ / 1sin2ϕ 
Answer» A. ka = 1sinϕ / 1+sinϕ 
71. 
Coefficient of passive earth pressure kp 
A.  kp = 1sinϕ / 1+sinϕ 
B.  kp = 1sin2ϕ / 1+sin2ϕ 
C.  kp = 1+sinϕ / 1sinϕ 
D.  kp = 1+sin2ϕ / 1sin2ϕ 
Answer» C. kp = 1+sinϕ / 1sinϕ 
72. 
The relation between ka = coefficient of active earth pressure and kp = coefficient of passive earth pressure is 
A.  kp =3 x ka 
B.  ka =3 x kp 
C.  kp =9 x ka 
D.  ka =9 x kp 
Answer» C. kp =9 x ka 
73. 
The vertical stem of cantilever retaining wall is subjected to 
A.  varying earth pressure developing tensile stresses on earth side 
B.  varying earth pressure developing tensile stresses on opposite side of earth side 
C.  varying large upward soil pressure 
D.  downward force due to selfweight of slab 
Answer» A. varying earth pressure developing tensile stresses on earth side 
74. 
The heel slab of cantilever retaining wall is subjected to

A.  1 ,2 and 3 
B.  only 2 and 3 
C.  only 1 and 3 
D.  2, 3 and 4 
Answer» D. 2, 3 and 4 
75. 
The toe slab of cantilever retaining wall is subjected to

A.  1 ,2 and 3 
B.  only 2 and 3 
C.  only 1 and 3 
D.  2, 3 and 4 
Answer» C. only 1 and 3 
76. 
To stabilize a concrete cantilever retaining wall against sliding, the ratio of sliding force to resisting force should be 
A.  ≥ 1.55 
B.  ≤ 1.55 
C.  ≥ 1.0 
D.  ≤ 0.645 
Answer» D. ≤ 0.645 
77. 
To stabilize a concrete cantilever retaining wall against sliding, the ratio of resisting force to sliding force should be 
A.  ≥ 1.55 
B.  ≤ 1.55 
C.  ≥ 1.0 
D.  ≤ 0.645 
Answer» A. ≥ 1.55 
78. 
In retaining wall to prevent the sliding of wall sometimes 
A.  shear key is provided 
B.  bending key is provided 
C.  ankle key is provided 
D.  bearings are provided 
Answer» A. shear key is provided 
79. 
If the angle of repose is 31º the coefficient of active earth pressure is 
A.  0.29 
B.  0.32 
C.  0.3 
D.  0.22 
Answer» B. 0.32 
80. 
The temperature and shrinkage reinforcement provided in retaining wall for mild steel 
A.  0.12% of gross sectional area 
B.  0.15% of gross sectional area 
C.  0.51% of gross sectional area 
D.  0.21% of gross sectional area 
Answer» B. 0.15% of gross sectional area 
81. 
The temperature and shrinkage reinforcement provided in retaining wall for HYSD reinforcement is 
A.  0.12% of gross sectional area 
B.  0.15% of gross sectional area 
C.  0.51% of gross sectional area 
D.  0.21% of gross sectional area 
Answer» A. 0.12% of gross sectional area 
82. 
For stability of retaining wall against retaining wall the factor of safety against overturning 
A.  should not less than 1.55 
B.  should not more than 1.55 
C.  should not less than 1.00 
D.  1 
Answer» A. should not less than 1.55 
83. 
If embankment is sloping at an angle of 18º to the horizontal, the coefficient of active earth pressure is 
A.  0.3 
B.  0.36 
C.  3.6 
D.  3 
Answer» B. 0.36 
84. 
If angle of repose is 30º then Coefficient of active earth pressure ka 
A.  3 
B.  9 
C.  1/3 
D.  1/9 
Answer» C. 1/3 
85. 
If angle of repose is 30º then Coefficient of passive earth pressure kp 
A.  3 
B.  9 
C.  1/3 
D.  1/9 
Answer» A. 3 
86. 
The maximum permissible eccentricity of a retaining wall of width B to avoid failure in tension is 
A.  b/2 
B.  b/3 
C.  b/6 
D.  b/12 
Answer» C. b/6 
87. 
Let height of retaining wall is 5.1m, ϒ=unit weight of backfill is 18kN/m3 and ka = coefficient of active earth pressure is 0.32, then total pressure at height 5.1m below top of the wall is given by 
A.  74.90 kn 
B.  79.40 kn 
C.  94.70 kn 
D.  97.40 kn 
Answer» A. 74.90 kn 
88. 
Let height of retaining wall is 5.1m, ϒ=unit weight of backfill is 18kN/m3 and ka = coefficient of active earth pressure is 0.32, then bending moment at height 5.1m below top of the wall is given by 
A.  123.74 knm 
B.  137.24 knm 
C.  127.34 knm 
D.  124.73 knm 
Answer» C. 127.34 knm 
89. 
In axially prestressed concrete members, the steel is under 
A.  compression 
B.  tension 
C.  torsion 
D.  shear 
Answer» B. tension 
90. 
In axially prestressed members, the concrete is under 
A.  tension 
B.  compression 
C.  torsion 
D.  shear 
Answer» B. compression 
91. 
Prestressing is possible by using 
A.  mild steel 
B.  highstrength deformed bars 
C.  hightensile steel 
D.  all of the above 
Answer» C. hightensile steel 
92. 
Prestressing steel has an ultimate tensile strength nearly 
A.  twice that of hysd bars 
B.  thrice that of mild steel reinforcements 
C.  four times that of hysd bars 
D.  six times that of hysd bars 
Answer» C. four times that of hysd bars 
93. 
Prestressing is economical for members of 
A.  long span 
B.  medium span 
C.  short span 
D.  all of the above 
Answer» A. long span 
94. 
Linear prestressing is adopted in 
A.  circular tanks 
B.  pipes 
C.  beams 
D.  both a and b 
Answer» C. beams 
95. 
Circular prestressing is advantageous in 
A.  beams 
B.  columns 
C.  pipes and tanks 
D.  both a and b 
Answer» C. pipes and tanks 
96. 
Prestressing wires in electric poles are 
A.  concentric 
B.  eccentric 
C.  parabolic 
D.  biaxial 
Answer» A. concentric 
97. 
In the construction of large circular water tanks, it is economical to adopt 
A.  reinforced concrete 
B.  prestressed concrete 
C.  steel 
D.  none of the above 
Answer» B. prestressed concrete 
98. 
In cablestayed bridges, the cables supporting the deck of the bridge are under 
A.  compression 
B.  torsion 
C.  shear 
D.  tension 
Answer» D. tension 
99. 
The grade of concrete for prestressed members should be in the range of 
A.  m20 to m30 
B.  m80 to m100 
C.  m30 to m60 
D.  m60 to m80 
Answer» C. m30 to m60 
100. 
Highstrength mixes should have a water/cement ratio of 
A.  0.6 to 0.8 
B.  0.3 to 0.4 
C.  0.2 to 0.3 
D.  0.4 to 0.6 
Answer» B. 0.3 to 0.4 
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